The given question is incomplete. The complete question is:
A chemist adds 95.0 ml of a 1.5M aluminum chloride solution to a flask. Calculate the mass in grams of aluminum chloride the chemist has added to the flask. Be sure your answer has the correct number of significant digits.
Answer: 19.0 grams
Explanation:
Molarity of a solution is defined as the number of moles of solute dissolved per liter of the solution.
where,
n = moles of solute
= volume of solution in ml
moles of 
= 
Now put all the given values in the formula of molarity, we get
Therefore, the mass in grams of aluminum chloride the chemist has added to the flask is 19.0
Answer:
The answer to your question is ΔP = 1.57 atm
Explanation:
Data
moles = 1
volume = 0.5 L
Temperature = 22°C or 295°K
Pressure = ?
a) Ideal Gas
PV = nRT R = 0.082 atm L / mol°K
-Solve for P
P = nRT/V
P = (1)(0.082)(295)/ 0.5
P = 23.944/ 0.5
P = 47.9 atm
b) Van der Waals
(P + a/v²)(v - b) = RT
- Substitution
(P + 1.345/0.5²)(0.5 - 0.03219) = (0.082)(295)
- Simplification
(P + 5.38)(0.46781) = 24.19
P + 5.38 = 24.19/0.46781
P + 5.38 = 51.71
-Solve for P
P = 51.71 - 5.38
P = 46.33 atm
c) The difference between both Pressures is
ΔP = 47.9 - 46.33
= 1.57 atm
Answer:
Option B and D
Explanation:
The Gibb's free energy also referred to as the gibb's function represented with letter G. it is the amount of useful work obtained from a system at constant temperature and pressure. The standard gibb's free energy on the other hand is a state function represented as Delta-G, as it depends on the initial and final states of the system.
A feasible way to synthesize the product entails the spontaneity of the reaction.
The spontaneity of a reaction is explained by the standard gibb's free energy.
If Delta-G = -ve ( the reaction is spontaneous)
if Delta -G = +ve ( the reaction is non-spontaneous)
if Delta-G = 0 ( the reaction is at equilibrium)
Hence the option (B and D) with negative Gibb's free energy are the reaction that are spontaneous.
Prophase is the first stage of Mitosis and also the beginning stage in which the cell prepares itself to begin to other stages of Mitosis.
Hope this helps!!!
