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3 years ago

14

Can someone name this alkane, please ?

1 answer:

Sloan [31]3 years ago

8 0

5-Methyl-5-ethyldecane should be the answer .

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A chemist studies the reaction below. 2NO(g) + Cl2(g) 2NOCl(g) He performs three experiments using different concentrations and

Dmitry_Shevchenko [17]

Answer:

1. $Rate =k [NO]^{2}[Cl_{2}]$

2. $k= 0.42 \frac{L^{2}}{mol^{2}*s}$

Explanation:

$Rate =k [NO]^{m}[Cl_{2}]^{n}$

$Rate1 = k[0.4]^{m}[0.3]^{n}=0.02\\Rate 2=k [0.8]^{m}[0.3}]^{n}=0.08\\\\\frac{Rate1}{Rate2}=\frac{0.02}{0.08} =\frac{k[0.4]^{m}[0.3]^{n}}{k[0.8]^{m}[0.3]^n}} \\\\\frac{1}{4} =(\frac{1}{2} )^{m},\\m=2$

$Rate3 =k [0.8]^{m}[0.6]^{n}=0.16\\Rate 2= k[0.8]^{m}[0.3}]^{n}=0.08\\\\\frac{Rate3}{Rate2}=\frac{0.16}{0.08} =\frac{k[0.8]^{m}[0.6]^{n}}{k[0.8]^{m}[0.3]^n}} \\\\\frac{2}{1} =(\frac{2}{1} )^{n},\\n=1$

$Rate =k [NO]^{2}[Cl_{2}]^{1}$

$Rate =k [NO]^{2}[Cl_{2}]^{1}\\Rate 1=k [0.4]^{2}[0.3]^{1} =0.02\\k*0.16*0.3=0.02\\k=\frac{0.02}{0.16*0.3}=\frac{1}{8*(\frac{3}{10} )}=\frac{5}{12} = 0.42 \frac{L^{2}}{mol^{2}*s}$

6 0

3 years ago

Match each organ to its function. Tiles bone heart stomach lung Pairs pumps blood through the body Both provides structure for t

solniwko [45]

Heart: Pumps blood through the body
Bone: Provides structure
Stomach: Breaks down food into small particles
Lungs: Oxygenates blood

7 0

3 years ago

Read 2 more answers

Can someone me Help please

soldier1979 [14.2K]

Independent would be the amount of sugar given and the dependent would be the amount of cavities

Scientists have control groups so they can have evidence to show the difference between that one and the experimental ones.

And the independent variable is the one that changes because with out it changing you wouldn't get different results.

I could be wrong tho sorryyy! but i hope this helps

8 0

3 years ago

A 5 gram round ball has a density of 1.25 grams/milliliter. What is the volume of the round ball?

Arlecino [84]

Explanation:

m=5g

density=1.25g/ml

density=m/v

v=m/density=5/1.25

4 0

3 years ago

If an object is moving right at 10 N and a force is applied from the left at 8N, what is the net force on the object?

ryzh [129]

Answer:

If an object is moving at a constant speed in a constant rightward direction, then the acceleration is zero and the net force must be zero.

5 0

3 years ago