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mixer [17]
3 years ago
11

A section of the periodic table is shown below which of the following statements is true?

Chemistry
2 answers:
Setler79 [48]3 years ago
6 0
Oxygen is more reactive than fluorine because oxygen needs only one electron to fill its outermost shell.
goldfiish [28.3K]3 years ago
5 0
Neon is inert because its outermost shell is complete. Neon is already in noble gas configuration and it will be very difficult to change this, essentially making it inert.

Nitrogen is inert because its outermost shell has eight electrons. Nitrogen's outermost shell only has 3 electrons so it is generally unstable and wants to gain 3 more to be in noble gas configuration.

Oxygen is more reactive than fluorine because oxygen needs only one electron to fill its outermost shell. This is just completely false, Fluorine is the most reaction element there is.

Fluorine is more reactive than neon because fluorine has to lose only one electron to fill its outermost shell. Although fluorine is more reactive, this is because it only needs to GAIN one more electron, not lose one more.
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A first-order reaction has a half-life of 29.8 s . How long does it take for the concentration of the reactant in the reaction t
lutik1710 [3]

Answer : The time taken for the concentration of the reactant in the reaction to fall to one-fourth of its initial value is, 12.4 seconds.

Explanation :

Half-life = 29.8 s

First we have to calculate the rate constant, we use the formula :

k=\frac{0.693}{t_{1/2}}

k=\frac{0.693}{29.8s}

k=0.0232s^{-1}

Now we have to calculate the time passed.

Expression for rate law for first order kinetics is given by:

t=\frac{2.303}{k}\log\frac{a}{a-x}

where,

k = rate constant  = 0.0232s^{-1}

t = time passed by the sample  = ?

a = let initial amount of the reactant  = x M

a - x = amount left after decay process = x-\frac{1}{4}\times (x)=\frac{3}{4}\times (X)=\frac{3x}{4}M

Now put all the given values in above equation, we get

t=\frac{2.303}{0.0232s^{-1}}\log\frac{x}{(\frac{3x}{4})}

t=12.4s

Therefore, the time taken for the concentration of the reactant in the reaction to fall to one-fourth of its initial value is, 12.4 seconds.

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4 years ago
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UHHHHHHHH IDRK TRY THE LINK ABOVE
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Read 2 more answers
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