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Darya [45]
2 years ago
5

State the various transformations applied to the base function f(x)=|x| to obtain a graph of the function g(x) = |x| − 2.

Mathematics
1 answer:
Molodets [167]2 years ago
6 0

Horizontal shift of 1 unit to the left and a vertical shift downward of 2 units.

<h3>Transformation of function</h3>

Transformation technique is a way of changing the position of an object on an xy-plane.

Given the parent function of a modulus function f(x) = |x|, the graph of the function g(x) = |x| - 2 shows a vertical translation of the parent function down by 2 units.

The resulting graph of the translated function is as shown below

Learn more on translation here: brainly.com/question/1046778

#SPJ1

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A student determined that the area of the segment of c shown above is Asegment = 137.71 ft2. The student's work is shown below.
ivolga24 [154]

Answer:

Option D. The student did not use the correct formula to calculate the area of the segment

Step-by-step explanation:

step 1

Find the area of the isosceles triangle

Applying the law of sines

A=\frac{1}{2}(12^{2})sin(60\°)=62.35\ ft^{2}

step 2

Find the area of the sector

The area of the sector is 1/6 of the area of the circle

so

A=\pi r^{2}/6

substitute the value

A=(3.14)(12)^{2}/6=75.36\ ft^{2}

step 3

Find the area of the segment

The area of the segment is equal to the area of sector minus the area of triangle

A=75.36\ ft^{2}-62.35\ ft^{2}=13.01\ ft^{2}

therefore

The student did not use the correct formula to calculate the area of the segment

4 0
3 years ago
Solving simultaneous equations by algebraic methods <br> 3a+4x=29<br> 2a-3x=-9
kogti [31]
<span>3a+4x=29 (1st)
2a-3x=-9 (2nd)

multiply (1st) by 3 and (2nd) by 4

</span>9a + 12x = 87 (1st)
8a - 12x = -36 (2nd)
---------------------add
17a = 51
   a = 3

<span>2a-3x=-9
</span><span>2(3)-3x=-9
6 - 3x = -9
-3x = -15
   x = 5

answer
x = 5 and a = 3</span>
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Vanyuwa [196]

Answer:

C) -6-(-3)=3

Step-by-step explanation:

-6-(-3)=

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So the third one is incorrect

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Order the numbers in the set from least to greatest.
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