Answer:
Area Of a Right Angled∆
=><em><u> </u></em><em><u>1</u></em><em><u>/</u></em><em><u>2</u></em><em><u> </u></em><em><u>x </u></em><em><u>Base </u></em><em><u>x </u></em><em><u>Height</u></em>
Area of a ∆ Using Heron's Formula
=>
Where
- S = Semiperimeter
- a ,b& c = sides of the ∆
Answer:
b₁ = (2a – b₂h)/h; b₁ = (2a)/h – b₂; h = (2a)/(b₁ + b₂)
Step-by-step explanation:
A. <em>Solve for b₁
</em>
a = ½(b₁ + b₂)h Multiply each side by 2
2a = (b₁ + b₂)h Remove parentheses
2a = b₁h + b₂h Subtract b₂h from each side
2a - b₂h = b₁h Divide each side by h
b₁ = (2a – b₂h)/h Remove parentheses
b₁ = (2a)/h – b₂
B. <em>Solve for h
</em>
2a = (b₁ + b₂)h Divide each side by (b₁ + b₂)
h = (2a)/(b₁ + b₂)
Answer:
y = 6x
Step-by-step explanation:
You can easily find the slope by using slope formula:
(y2-y1) / (x2-x1) (the numbers are subscript)
E.g: (24-12) / (4-2) = 12/2 = 6
m(slope) = 6
Hope this helped :)
(You can also check if it’s correct by inputting the coords into the equation, seeing if all solutions are aplicable).
Answer:
The solution to the system of equations are;
x = -4/3
y = 5/3
Step-by-step explanation:
To find the Solution, we would carry the Operation simultaneously.
4x + 2 = -2y .........(i)
6y - 18 = 6x ..........(ii)
First let's rearrange the equations, to make the journey smoother
2y + 4x = -2 ...........(iii)
6y - 6x = 18 ...........(iv)
Let's Multiply equation (III) by 3 so as to have a uniform spot to begin elimination.
3.2y + 3.4x = -2 . 3
6y + 12x = -6............... (v)
Let's subtract equation (v) from equation (iv)
= 0y - 18x = 24
-18x = 24
x = - 24 / 18
x = -4/3
Let's substitute (x = -4/3) in equation (ii), so that we can solve for the value of y:
6y - 18 = 6x
6y - 18 = 6 (-4/3)
6y - 18 = -8
6y = -8 + 18
6y = 10.
y = 10 / 6
y = 5/3
The solution to the system of equations are;
x = -4/3
y = 5/3
We can find m∠BCD like follows: m∠BCD=90°-45°=45<span>°
Now, m</span><span>∠DBC= 180°-(90°+45°)=45°
Remember that </span>
, so
We know that hypotenuse= BC= 3in and
=∠DBC)=45°, so replacing the values we get:
We can conclude that the segment CD is 2.12 in
