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Answer:
The equation of line 3 is;
y = + 6
Step-by-step explanation:
Line 1 passes through the points A(-15,-8) andn B(-3,0)
Line 2 has equation shown below;
5x - 3y + 18 = 0
Line 3 is parallel to line 1 and has the same y-intercept as line 2.
We are to determine the equation of line 3.
<u>Equation of line 1:</u>
<u />
Slope = change in y-axis ÷ change in x-axis
The slope of line 1 =
Picking another point (x,y) on the line;
Slope =
y = + 2 (this is the equation of line 1)
<u>Equation of line 2:</u>
<u />
We put the equation given, of line 2, in the cartesian plane format;
3y = 5x + 18
y = + 6
Finally, the equation of line 2 is;
y = 1 + 6
<u>Equation of line 3:</u>
<u />
Given: Line 3 is parallel to line 1
The slopes of two parallel lines are the same so line 3 has a slope of
Given: Line 3 has the same y-intercept as line 2
The y-intecept of line 2 is 6 (y-intercept is the value of y when x = 0)
So the equation of line 3 is;
y = + 6
Answer:
Option (4)
Step-by-step explanation:
Equation of a line passing through a point and with slope 'm' is,
y - y₁ = m(x - x₁)
Given → Slope 'm' = -2
Point through which the line is passing is (-1, -2)
x₁ = -1 and y₁ = -2
Therefore, equation will be,
y + 2 = -2(x + 1)
y = -2x - 2 - 2
y = -2x - 4
Option (4) is the correct option.