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fredd [130]
2 years ago
8

A walking path across a park is represented by the equation y=-2x-7. A

Mathematics
1 answer:
liq [111]2 years ago
6 0

The equation of the new path is y = -1/2x - 4

<h3>How to determine the equation?</h3>

The equation is given as:

y = 2x - 7

A linear equation is represented as:

y = mx + c

Where m represents slope

This means that:

m = 2

Let the slope of the perpendicular equation be n.

The condition of perpendicular lines is

n = -1/m

So, we have:

n = -1/2

The equation of the new path is then calculated using:

y = n(x - x1) + y1

So, we have:

y= -1/2(x + 2) - 3

Expand

y = -1/2x - 4

Hence, the equation of the new path is y = -1/2x - 4

Read more about linear equations at:

brainly.com/question/14323743

#SPJ1

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Your classmate is correct, though this is not explicitly what the midpoint formula is necessarily set out to do. If one is given two sets of endpoints, one can discover the midpoint by finding the mean distance between these two endpoints. For example, if two points are 10 and 2, all you need do to find the midpoint is add the two poles and divide them by 2 (that is, find the average). The same applies for coordinate geometry, except with additional variables, the formula to find the coordinates of a midpoint is: M= (x1+x2/2, y1+y2/2). Thus, two averages (of both the x coordinates and y coordinates are taken). Your classmate is correct if two endpoints are given, think of a line with two poles, the middle of this line must be the midpoint. 
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4 years ago
Pls help I don’t understand
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That is all the work needed to solve this problem

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3 years ago
H(x)=-x^2+6x. So what is the value of h(2)
crimeas [40]

✩ Answer:

 ✧・゚: *✧・゚:*✧・゚: *✧・゚:*✧・゚: *✧・゚:*

  \bold{Hello!}\\\bold{Your~answer~is~below!}

✩ Step-by-step explanation:

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✺ Quadratic polynomials can be factored using the transformation ax^2+bx+c=a(x-x_{1})(x-x_{2} ), where x_{1} and x_{2} are the solutions of the quadratic equation ax^2+bx+c=0:

  • -x^2+6x=0

✺ All equations of the form ax^2+bx+c=0 can be solved using the quadratic formula:

  • -b=\frac{+}\\\sqrt{b^2-4ac}\\~~~~~~~~~~~~~2a

✺ The quadratic formula gives two solutions, one when ± is addition and one when it is subtraction:

  • x=\frac{\sqrt{-6\frac{+}\\\sqrt{6^2}}}{2(-1)}

✺ Take the square root of 6^2:

  • x=\frac{\sqrt{-6\frac{+}\\{6}}}{2(-1)}

✺ Multiply 2 times -1:

  • x=\frac{\sqrt{-6\frac{+}\\{6}}}{-2}

✺ Now solve the equation x=\frac{\sqrt{-6\frac{+}\\{6}}}{-2} when ± is plus. Add -6 to 6:

  • x=\frac{0}{-2}

✺ Divide 0 by -2:

  • x=0

       -OR-

✺ Now solve the equation x=\frac{\sqrt{-6\frac{+}\\{6}}}{-2} when ± is minus. Subtract 6 from -6:

  • x=\frac{-12}{-2}

✺ Divide -12 by -2:

  • x=6

✺  Optional : Factor the original expression using ax^2+bx+c=a(x-x_{1})(x-x_{2} ). Substitute 0 for x_{1} and 6 for x_{2}:

  • -x^2+6x=-x(x-6)

✩ Answer:

✺ <u>Factored Form</u>: x(x-6)

✺ <u>Exact Form</u>: x=6

✺ <u>Graph Point Form</u>: x=(6,0)

Hope~this~helps~and,\\Best~of~luck!\\\\~~~~~-TotallyNotTrillex

             "ටᆼට"

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Answer:

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I believe the answer would be C, but I'm not sure.

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