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Maru [420]
1 year ago
12

Which ordered pair makes both inequalities true?

Mathematics
1 answer:
Mamont248 [21]1 year ago
7 0

The ordered pair that makes both inequalities true is (4,0).

we have

y<3x-1 ----> inequality A

y > –x + 4----> inequality B

we know that

If an ordered pair is a solution to the system of inequalities, then the ordered pair must satisfy both inequalities (makes true both inequalities)

Verify each ordered pair

case 1) (4,0)

Inequality A

0<3(4)-1 ----> is true

Inequality B

0> –4 + 4 ----> is true

<h3>What is inequality?</h3>

A statement of an order relationship greater than, greater than or equal to, less than, or less than or equal to between two numbers or algebraic expressions.

So, The ordered pair makes both inequalities true

case 2) (1,2)

Inequality A

2< 3(1) – 1

2<3-1

2<2----> is not true

So the ordered pair does not make both inequalities true

case 3) (0,4)

Inequality A

0 < 3(4) – 1

0<12-1

0<11 ----> is not true

So, the ordered pair does not make both inequalities true

case 4) (2,1)

Inequality A

1< 3(2) – 1

1<6-1

1<5----> is true

Inequality B

1\geq -2+4

1\geq 2 ----> is not true

So the ordered pair does not make both inequalities true.

To learn more about the inequalities visit:

brainly.com/question/24372553

#SPJ1

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