Answer:
r = -12cos(θ)
Step-by-step explanation:
The usual translation can be used:
Putting these relationships into the formula, we have ...
(r·cos(θ) +6)² +(r·sin(θ))² = 36
r²·cos(θ)² +12r·cos(θ) +36 +r²·sin(θ)² = 36
r² +12r·cos(θ) = 0 . . . . subtract 36, use the trig identity cos²+sin²=1
r(r +12cos(θ)) = 0
This has two solutions for r:
r = 0 . . . . . . . . a point at the origin
r = -12cos(θ) . . . the circle of interest
No, becasue of PEMDAS
so parenthasees first
exponents next
mulitplciation next
(-2)^4=-2 times -2 times -2 times -2=positive number since even number of negative signs
-2^4=-1 times 2^2=-1 times 2 times 2 times 2 times 2=negative number since odd number of negative signs
Answer:
Answer is A, A=3
Step-by-step explanation:
Answer:
w<33/4
Step-by-step explanation:
8w-35<3-(5-4w)
8w-35<3-5+4w
8w-35<-2+4w
8w-4w-35<-2
4w-35<-2
4w<-2+35
4w<33
w<33/4
D! I’ve taken this
Please mark me as brainliest!