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AlekseyPX
3 years ago
9

Evaluate the expression when x=-5. Huiles x2 +8x+2

Mathematics
2 answers:
IgorC [24]3 years ago
5 0

Answer:

52

Step-by-step explanation:

(2×5)+(8×5)+2

10+40+2

52

Alekssandra [29.7K]3 years ago
3 0

Answer:

52

Step-by-step explanation:

5*2+8*5+2=52

Evaluation simplified

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Right triangles 1,2 and 3 are given to its all their angle measures and approximate side lengths
Ede4ka [16]

Answer:

5.4 units

Step-by-step explanation:

From the figure ,it's clear that   sin(50) = PQ/7

Then

PQ = 7×sin(50) = 5.362311101833

Therefore the approximate length of PQ I saw 5.4

6 0
2 years ago
Give the equation of a line that goes through the point ( − 21 , 2 ) and is perpendicular to the line 7 x − 4 y = − 12 . Give yo
nlexa [21]

Given:

Equation of line 7x-4y=-12.

To find:

The equation of line  that goes through the point ( − 21 , 2 ) and is perpendicular to the given line.

Solution:

The given equation of line can be written as

7x-4y+12=0

Slope of line is

\text{Slope}=-\dfrac{\text{Coefficient of x}}{\text{Coefficient of y}}

m_1=-\dfrac{7}{(-4)}

m_1=\dfrac{7}{4}

Product of slopes of two perpendicular lines is -1. So, slope of perpendicular line is

m_1m_2=-1

m_2=-\dfrac{1}{m_1}

m_2=-\dfrac{4}{7}           [\because m_1=\dfrac{7}{4}]

Now, the slope of perpendicular line is m_2=\dfrac{4}{7} and it goes through (-21,2). So, the equation of line is

y-y_1=m_2(x-x_1)

y-2=-\dfrac{4}{7}(x-(-21))

y-2=-\dfrac{4}{7}x-\dfrac{4}{7}(21)

y-2=-\dfrac{4}{7}x-12

y=-\dfrac{4}{7}x-12+2

y=-\dfrac{4}{7}x-10

Therefore, the required equation in slope intercept form is y=-\dfrac{4}{7}x-10.

7 0
3 years ago
Using the given rectangular box, find the following.... PLEASE HELP ME ASAP!! SUCK AT MATH!!!
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7 0
3 years ago
What is 3,000 subtracted from 1/10
nadezda [96]
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4 0
3 years ago
Read 2 more answers
Solve the equation A = bh for b. b = Ah b = A/h b = h/A b = h – A Solve the equation A = bh for b. b = Ah b = A/h b = h/A b = h
Leto [7]

Answer:

The answer is "b=\frac{A}{h}".

Step-by-step explanation:

Therefore in this question the "bh" were the multiplied and these values includes the variable which is solving by the isolating of "b".

Let's Divides the both sides for h.

\to \frac{A}{h} = \frac{bh}{h}\\\\\to \frac{A}{h} = b\\\\\to b= \frac{A}{h}

7 0
3 years ago
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