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AlekseyPX
3 years ago
9

Evaluate the expression when x=-5. Huiles x2 +8x+2

Mathematics
2 answers:
IgorC [24]3 years ago
5 0

Answer:

52

Step-by-step explanation:

(2×5)+(8×5)+2

10+40+2

52

Alekssandra [29.7K]3 years ago
3 0

Answer:

52

Step-by-step explanation:

5*2+8*5+2=52

Evaluation simplified

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Prove that 3^17−3^15+3^13 is divisible by 73.<br><br> HELPPPPPP PLEASEEE
Fiesta28 [93]

Answer:

Well 3^17-3^15+3^13 equals 116,385,579

Now divide that by 73

So 116,385,579 ÷ 73

That equals 1,594,323

Hope this helps

4 0
2 years ago
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A translation occurred that moved 4 units left and 3 units up. If Point A was at ( -3, -2 ), what are the coordinates of A'?
snow_lady [41]

Answer:

I think -7; +1

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4 0
3 years ago
How do i solve this​
Troyanec [42]

Answer:

f=11

Step-by-step explanation:

If t=7, we can substitute it into the original equation:

f=(2)(7)-3

Simplify:

f=14-3

f=11

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3 0
3 years ago
what is the answer here 90 student went to the zoo, 3 had hamburger milk and cake; had 5 milk and hamburger; 10 had cake and mil
dangina [55]

Answer:

a) 37

b) 2

c) 17

d) 8

Step-by-step explanation:

90 Students went to the zoo. 3 had hamburger, milk and cake; 5 had milk and hamburger, 10 had cake and milk; 8 had cake and hamburger; 24 had hamburger; 38 had cake; 20 had milk. How many had a. nothing b. cake only c. milk only d. hamburger only

Solution:

Let h represent students that ate hamburger, m represent students that had milk and c represent students that had cake.

Given that:

n(h ∩ m ∩ c) = 3, n(m ∩ h) = 5, n(c ∩ m) = 10, n(c ∩ h) = 8, n(h) = 24, n(c) = 38, n(m) = 20

The number of students that had nothing = n(h  ∪ m ∪ C)'

The number of students that had only milk = n(m ∩ h' ∩ C')

The number of students that had only cake = n(m' ∩ h' ∩ C)

The number of students that had only hamburger = n(m' ∩ h ∩ C')

a) n(m ∩ h' ∩ C') = n(m) - n(m ∩ h) - n(c ∩ m) - n(h ∩ m ∩ c) = 20 - 5 - 10 - 3 = 2

n(m' ∩ h ∩ C') = n(h) - n(m ∩ h) - n(c ∩ h) - n(h ∩ m ∩ c) = 24 - 5 - 8 - 3 = 8

n(m' ∩ h' ∩ C) = n(m) - n(m ∩ c) - n(c ∩ h) - n(h ∩ m ∩ c) = 38 - 10 - 8 - 3 = 17

n(m ∩ h' ∩ C') + n(m' ∩ h ∩ C') + n(m' ∩ h' ∩ C) + n(h  ∪ m ∪ C)' + n(h ∩ m ∩ c) + n(m ∩ h) + n(c ∩ m) + n(c ∩ h) = 90

2 + 8 + 17 + 5 + 10 + 8 + 3 + n(h  ∪ m ∪ C)' = 90

53 + n(h  ∪ m ∪ C)' = 90

n(h  ∪ m ∪ C)' = 37

b) n(m' ∩ h' ∩ C) = 17

c) n(m ∩ h' ∩ C') = 2

d) n(m' ∩ h ∩ C') = 8

4 0
2 years ago
A line segment has the endpoints P(4, 7) and Q(6, 7). Find the coordinates of its midpoint M.
tatuchka [14]

Answer:

(5, 7)

Step-by-step explanation:

M = (x1 + x2/2 , y1 + y2/2)

M = ( 4 + 6 /2 , 7 + 7 / 2)

M = 5, 7

4 0
3 years ago
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