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2 years ago

6

Se quiere cubrir una pared con vidrios de forma triangular. La pared mide 36 m de largo y 9V3 m de alto.

1 answer:

Eddi Din [679]2 years ago

4 0

Based on the dimensions of the wall and the triangular glass, the number of mirrors needed is 215 mirrors.

<h3>What number of mirrors are needed?</h3>

First find the area of the wall:

= 36 x 93

= 3,348 m²

The area of the triangle, assuming it is an equilateral triangle is:

= (√3/4) x 6²

= 15.59 m²

The number of mirrors needed is:

= 3,348 / 15.59

= 215 mirrors

Find out more on the area of an equilateral triangle at brainly.com/question/1099318.

#SPJ1

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Use the shell method to write and evaluate the definite integral that represents the volume of the solid generated by revolving

faust18 [17]

Answer:

$Volume = \frac{384}{7}\pi$

Step-by-step explanation:

Given (Missing Information):

$y = x^\frac{3}{2}$ ; $y = 8$ ; $x=0$

Required

Determine the volume

Using Shell Method:

$V = 2\pi \int\limits^a_b {p(y)h(y)} \, dy$

First solve for a and b.

$y = x^\frac{3}{2}$ and $y = 8$

Substitute 8 for y

$8 = x^\frac{3}{2}$

Take 2/3 root of both sides

$8^\frac{2}{3} = x^{\frac{3}{2}*\frac{2}{3}}$

$8^\frac{2}{3} = x$

$2^{3*\frac{2}{3}} = x$

$2^2 = x$

$4 =x$

$x = 4$

This implies that:

$a = 4$

For $x=0$

This implies that:

$b=0$

So, we have:

$V = 2\pi \int\limits^a_b {p(y)h(y)} \, dy$

$V = 2\pi \int\limits^4_0 {p(y)h(y)} \, dy$

The volume of the solid becomes:

$V = 2\pi \int\limits^4_0 {x(8 - x^{\frac{3}{2}}}) \, dx$

Open bracket

$V = 2\pi \int\limits^4_0 {8x - x.x^{\frac{3}{2}}} \, dx$

$V = 2\pi \int\limits^4_0 {8x - x^{\frac{2+3}{2}}} \, dx$

$V = 2\pi \int\limits^4_0 {8x - x^{\frac{5}{2}}} \, dx$

Integrate

$V = 2\pi * [{\frac{8x^2}{2} - \frac{x^{1+\frac{5}{2}}}{1+\frac{5}{2}}]\vert^4_0$

$V = 2\pi * [{4x^2 - \frac{x^{\frac{2+5}{2}}}{\frac{2+5}{2}}]\vert^4_0$

$V = 2\pi * [{4x^2 - \frac{x^{\frac{7}{2}}}{\frac{7}{2}}]\vert^4_0$

$V = 2\pi * [{4x^2 - \frac{2}{7}x^{\frac{7}{2}}]\vert^4_0$

Substitute 4 and 0 for x

$V = 2\pi * ([{4*4^2 - \frac{2}{7}*4^{\frac{7}{2}}] - [{4*0^2 - \frac{2}{7}*0^{\frac{7}{2}}])$

$V = 2\pi * ([{4*4^2 - \frac{2}{7}*4^{\frac{7}{2}}] - [0])$

$V = 2\pi * [{4*4^2 - \frac{2}{7}*4^{\frac{7}{2}}]$

$V = 2\pi * [{64 - \frac{2}{7}*2^2^{*\frac{7}{2}}]$

$V = 2\pi * [{64 - \frac{2}{7}*2^7]$

$V = 2\pi * [{64 - \frac{2}{7}*128]$

$V = 2\pi * [{64 - \frac{2*128}{7}]$

$V = 2\pi * [{64 - \frac{256}{7}]$

Take LCM

$V = 2\pi * [\frac{64*7-256}{7}]$

$V = 2\pi * [\frac{448-256}{7}]$

$V = 2\pi * [\frac{192}{7}]$

$V = [\frac{2\pi * 192}{7}]$

$V = \frac{\pi * 384}{7}$

$V = \frac{384}{7}\pi$

Hence, the required volume is:

$Volume = \frac{384}{7}\pi$

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2 years ago

The graph below shows the relationship between the number of months different students practiced tennis and the number of matche

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1 is 3 and 2 is y 2/1x

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3 years ago

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vlabodo [156]

According to the given function, it is found that fewer than 38.1% of U.S. voters will use punch cards or lever machines starting from the year of 2004.

<h3>What is the function?</h3>

$P(t) = -2.5t + 63.1$

In which t is the number of years after 1994.

It will be fewer than 38.1% when:

$P(t) < 38.1$

Hence:

$-2.5t + 63.1 < 38.1$

$-2.5t < -25$

$2.5t > 25$

$t > 10$

Fewer than 38.1% of U.S. voters will use punch cards or lever machines starting from the year of 2004.

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2 years ago

Which statement best describes the expression 3 + y ÷ 2?

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Hrmmmm let's see here...
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3 years ago

Find the radius of a circle with circumference of 45.84 meters. Use 3.14

alukav5142 [94]

Answer:

3.8 meters

Step-by-step explanation:

In order to find the circumference for a circle, we use the formula π(radius)²

The circumference give is 45.84 and the π given is 3.14

All we have to do is to just substitute them.

45.84 = 3.14(radius)²

45.84 / 3.14 = radius²

14.6 = radius²

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radius = 3.82 ≅ 3.8

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3 years ago

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