I started this and got distracted and never finished and it timed out. Focus Dean.
It's not the best graph; I assume the origin is the apparent origin and the y axis numbers go with the line above them.
This graph is M(V), M(V) is mass in kg of bucket with water volume V in liters
a) the mass of an empty bucket
That's the y intercept, M(0), eyeballing it around .7 kg
Answer: .7 kg
b) the mass of the bucket containing 1 liter of liquid
That's M(1), looks like 1.3 or so
Answer: 1.3 kg
c) the mass of one liter of liquid
That's the difference, M(1)-M(0), about .6 kg. We can get a better estimate from a longer slope, say (.5,1) to (3,3), (3-1)/(3-.5) = .8 kg.
Answer
: 0.8 kg
d) the volume of the liquid in the bucket, if the total mass of bucket with the liquid is 3 kg.
Solve M(V)=3
That has a solution from the graph V=3.
Answer: 3 liters
We have to put values of domain to find range
![\\ \ast\sf\longmapsto D_R=[-1,0,1]](https://tex.z-dn.net/?f=%5C%5C%20%5Cast%5Csf%5Clongmapsto%20D_R%3D%5B-1%2C0%2C1%5D)
Now
![\\ \ast\sf\longmapsto R_R=[-2,1,13]](https://tex.z-dn.net/?f=%5C%5C%20%5Cast%5Csf%5Clongmapsto%20R_R%3D%5B-2%2C1%2C13%5D)
Answer:
(7, - 3 )
Step-by-step explanation:
Under a clockwise rotation about the origin of 270°
a point (x, y ) → (- y, x )
Thus
(- 3, - 7 ) → (7, - 3 )
3 divided by 64 is 0.046875
Hello :
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B. second picture </span>
