1 year ago

Help if you can, and thanks

Mathematics

1 answer:

Tema [17]1 year ago

3 0

Answer:

letter D.

Step-by-step explanation:

beluga!

tank you sa points

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10m^3 of air weigh 13 kg.

Lemur [1.5K]

49.686‬ kg

Step-by-step explanation:

Since the density of the air remains constant in the question

We can represent this equation as a ratio;

10 m³ = 13 kg

(4.2 * 3.5 * 2.6) m³ = ? (x) kg

4.2 * 3.5 * 2.6 = 38.22

We cross multiply

38.22 * 13 = 10 * x

X = 496.86‬ /10

X = 49.686‬

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3 0

3 years ago

Divide. Show your work.<br><br> (6x^4-5x^3+6x^2)/2x^2

serg [7]

We can do like we did before, distribute the denominator,

$\bf \cfrac{6x^4-5x^3+6x^2}{2x^2}\implies \cfrac{6x^4}{2x^2}-\cfrac{5x^3}{2x^2}+\cfrac{6x^2}{2x^2}\implies \cfrac{6}{2}\cdot \cfrac{x^4}{x^2}-\cfrac{5}{2}\cdot \cfrac{x^3}{x^2}+\cfrac{6}{2}\cdot \cfrac{x^2}{x^2}
\\\\\\
3 x^4x^{-2}-\cfrac{5}{2}x^3x^{-2}+3x^2x^{-2}\implies 3x^{4-2}-\cfrac{5}{2}x^{3-2}+3x^{2-2}
\\\\\\
3x^2-\cfrac{5}{2}x+3x^0\implies 3x^2-\cfrac{5}{2}x+3$

6 0

3 years ago

What is 3m - 9/2,,,,,,,, Please help i need it now

Damm [24]

It would be $\frac{6m-9}{2}$ .