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koban [17]
1 year ago
8

Which equations are true?

Mathematics
1 answer:
ohaa [14]1 year ago
3 0

The correct answer from the task content is; Choice C; None of the above.

<h3>Which of the equations are true?</h3>

The equations can be evaluated as follows;

A) -x + (-x) =0

-x -x = -2x......Not True

B) x -(-x) = 0

x + x = 2x .....Not True.

On this note, it follows that none of the equations is true.

Read more on equations;

brainly.com/question/2972832

#SPJ1

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If a vehicle travels a distance of 5t^4-10t^2+6 miles in t+2 minutes what is the vehicles speed
satela [25.4K]

speed = distance/time
3 0
3 years ago
If S_1=1,S_2=8 and S_n=S_n-1+2S_n-2 whenever n≥2. Show that S_n=3⋅2n−1+2(−1)n for all n≥1.
Snezhnost [94]

You can try to show this by induction:

• According to the given closed form, we have S_1=3\times2^{1-1}+2(-1)^1=3-2=1, which agrees with the initial value <em>S</em>₁ = 1.

• Assume the closed form is correct for all <em>n</em> up to <em>n</em> = <em>k</em>. In particular, we assume

S_{k-1}=3\times2^{(k-1)-1}+2(-1)^{k-1}=3\times2^{k-2}+2(-1)^{k-1}

and

S_k=3\times2^{k-1}+2(-1)^k

We want to then use this assumption to show the closed form is correct for <em>n</em> = <em>k</em> + 1, or

S_{k+1}=3\times2^{(k+1)-1}+2(-1)^{k+1}=3\times2^k+2(-1)^{k+1}

From the given recurrence, we know

S_{k+1}=S_k+2S_{k-1}

so that

S_{k+1}=3\times2^{k-1}+2(-1)^k + 2\left(3\times2^{k-2}+2(-1)^{k-1}\right)

S_{k+1}=3\times2^{k-1}+2(-1)^k + 3\times2^{k-1}+4(-1)^{k-1}

S_{k+1}=2\times3\times2^{k-1}+(-1)^k\left(2+4(-1)^{-1}\right)

S_{k+1}=3\times2^k-2(-1)^k

S_{k+1}=3\times2^k+2(-1)(-1)^k

\boxed{S_{k+1}=3\times2^k+2(-1)^{k+1}}

which is what we needed. QED

6 0
2 years ago
How many hundreds in 148305
Wittaler [7]

148305:100=\dfrac{148305}{100}=1483.05\\\\Answer:\ In\ 148305\ is\ 1483\ hundreds

6 0
2 years ago
Read 2 more answers
Easy math i'll mark brainliest
german

Answer:

Q6: B Q7: D Q8: C Q9: D Q10: A

7 0
2 years ago
Read 2 more answers
The value of Peter's house has risen 10% a year for the last 3 years. if the value of Peter's home 3 years ago was $120,000.00,
pickupchik [31]
The answer is $132,000

First you multiply 120,000 by .10 which you get 12,000

Then you just add it and you find the answer
5 0
3 years ago
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