The maximum compression of the spring is 0.276 m
Step-by-step explanation:
First of all, we calculate the spring constant of the spring, by using Hooke's law:

where
F = 10 kN = 10,000 N is the force applied
x = 1.25 cm = 0.0125 m is the corresponding compression of the spring
k is the spring constant
Solving for k,

When the truck impacts with the spring, all the kinetic energy of the truck is converted into elastic potential energy of the spring, so we can write
(1)
where
m is the mass of the truck
v = 2 m/s is the initial speed of the truck
is the spring constant
x is the compression of the spring
The mass of the truck can be found from its weight:

So now we can re-arrange eq.(1) to find the compression, x:

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well, it's isosceles so use base angles theorem
the top angle is also x
90 + 2x = 180
subtract 90 from both sides
2x = 90
divide both sides by 2
x = 45 degrees
Answer:
21 moats
Step-by-step explanation:
.70 x 30 = 21
Answer:
42 ft, 60 ft, 84 ft
Step-by-step explanation:
let x be the shortest side , then the other 2 sides are 2x and x + 18, so
x + 2x + x + 18 = 186 , that is
4x + 18 = 186 ( subtract 18 from both sides )
4x = 168 ( divide both sides by 4 )
x = 42
Then lengths of sides are
x = 42 ft
2x = 2 × 42 = 84 ft
x + 18 = 42 + 18 = 60 ft
Step-by-step explanation:
Represent Wilbur with W and Orville with O
The equation connecting both flights is
W - 120 = O
W = 364 feet
364 - 120 = 246
O = 246