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Brut [27]
2 years ago
15

City planners are creating a 3-dimenslonal model of a city park to find the best placement for a new tennis court the city park

is on a rectangular plot of land that is 1,500 ft long and 600 ft wide the scale model of the park measures 7.5 ft x 3 ft if the dimensions of the actual tennis court must be 120 ft long and 60 ft wide, what are the dimensions
of the tennis court in the scale model
Mathematics
1 answer:
xxTIMURxx [149]2 years ago
5 0

The dimension of the tennis court in the scaled model is 0.6 ft long and 0.3 ft wide.

Given, a rectangular plot of land that is 1,500 ft long and 600 ft wide the scale model of the park measures 7.5 ft x 3 ft.

The actual tennis court must be 120 ft long and 60 ft wide, then we need to find the dimensions of the tennis court in the scale model.

<h3>What is a scaled model?</h3>

A scale model is a physical model which is geometrically similar to an object. Scale models are generally smaller than large prototypes such as vehicles, buildings, or people.

First, divide the original measurements by the scaled ones. We get

1500 ft. ÷7.5 ft = 200

600 ft. ÷ 3 ft. = 200

Now, divide tennis courts actual dimensions by 200. That is

120 ft. ÷ 200 = 0.6 ft

60 ft. ÷ 200 =  0.3 ft

Therefore, the dimension of the tennis court in the scaled model is 0.6 ft long and 0.3 ft wide.

To learn more about scale factor visit:

brainly.com/question/22312172.

#SPJ1

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Option B) h = 4.5t – 27 is the equation of the straight line that best models the height h, in centimeters, of the sunflower t days after it begins to grow.

                     

From the above graph we can see that from day 14 to day 35 , it is a straight line.

And equation of a straight line is   y = mx + c  or   y – y1 = m(x – x1)

                               Where, m =slope of the line

                                             c = intercept

the equation can be rewritten as  h – h1  = m(t – t1)                    (1)

So, to find the equation of line , first we will calculate the slope of the line.

To find the slope : m = (h2 – h1 ) / (t2 – t1)                     (2)

From the graph and the table given, the coordinates (t1 , h1 ) and ( t2 , h2 ) are (14 , 36.6) and (35, 131) respectively.

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now to find the equation of line we put the values in equation (1), we get

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h = 4.5t -63 + 36.6

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Hence the equation of the line is ,   option B) h = 4.5t -27

Learn more about the straight line here : brainly.com/question/6977417

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