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3 years ago

39= 3m - 12 I'd really appreciate it if you showed your work.

2 answers:

7 0

Flip the equation.
 $3m-12=39$
and add 12 to both sides.
 $3m-12+12=39+12$
$3m=51$
Now divide both sides by 3.
 $\frac{3m}{3}$ $= \frac{51}{3}$

Final answer: m=17

expeople1 [14]3 years ago

5 0

To solve for m;

39 = 3m -12

39+12 = 3m -12 + 12 (add 12 to both sides)

51 = 3m

51 ÷ 3 = m

17 =m

m =17

Hope that helps, let me know if you don't understand something :D

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It is given in the question functions f(x) as 3x+2 and g(x)=5-6x.

It is required to find $(f \circ g)(x)$ and $(g \circ f)(x)$ .

To find $(f \circ g)(x)$ , substitute g(x) for x in f(x) and simplify the expression.

To find $(g \circ f)(x)$ , substitute f(x) for x in g(x) and simplify the expression.

Step 1 of 2

Substitute g(x) for x in f(x) and simplify the expression.

$\begin{aligned}&(f \circ g)(x)=f(5-6 x) \\&(f \circ g)(x)=3(5-6 x)+2 \\&(f \circ g)(x)=15-18 x+2 \\&(f \circ g)(x)=17-18 x\end{aligned}$

Step 2 of 2

Substitute f(x) for x in g(x) and simplify the expression.

$\begin{aligned}&(g \circ f)(x)=g(3 x+2) \\&(g \circ f)(x)=5-6(3 x+2) \\&(g \circ f)(x)=5-18 x-12 \\&(g \circ f)(x)=-7-18 x\end{aligned}$

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2 years ago

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Answer :

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Step-by-step explanation :

To find the product of

$3 {y}^{2} z(2 {y}^{2} z + 4yz - y + z)$

First we expand the bracket ,

it implies that, we use the expression outside the bracket to multiply individual expressions inside the bracket.

Hence

$3 {y}^{2} z(2 {y}^{2} z + 4yz - y + z)$

$= 3 {y}^{2} z(2 {y}^{2} z) + 3 {y}^{2} z(4yz) - 3 {y}^{2} z(y )+3 {y}^{2} z( z)$

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meaning, when you are multiplying two expressions with the same bases , repeat one of the bases and add the exponents.

Then, simplify to obtain

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3 years ago