Jamel wants to buy a PS 5. He found it for $500
1 answer:
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Step-by-step explanation:
- 1
vector AB(3-(-6); 5-7)
vector AB(9;-2)
AB= =
- 2
M is the midpoint of AB
we have B(-5;10) and M(1;7)
let A(x;y)
(x-5)/2 = 1 ⇒ x-5 = 2⇒ x = 7
(10=y)/2 = 7⇒ 10+y = 14 ⇒y= 4
so : A(7;4)
- 3
the center of the circle is the midponit of the line joining both ends of the diameter
let A(x;y) be the other end
(-2+x)/2 = 2 ⇒ -2+x = 4⇒ x= 6
(5=y) = -1 ⇒ 5+y = -2 ⇒ y= -7
so the coordinates of the other end are (6; -7)
- 4
A,B and C are collinear such as AB=BC so b is the midpoint of AC
(-5+1)/2 = y ⇒ y = -4/2 ⇒ y = -2
((-3=x)/2 = 7 ⇒ -3+x = 14 ⇒ x = 17
so x= 17 and y = -2
Answer with Step-by-step explanation:
We are given that two independent tosses of a fair coin.
Sample space={HH,HT,TH,TT}
We have to find that A, B and C are pairwise independent.
According to question
A={HH,HT}
B={HH,TH}
C={TT,HH}
{HH}
={HH}
={HH}
P(E)=
Using the formula
Then, we get
Total number of cases=4
Number of favorable cases to event A=2
Number of favorable cases to event B=2
Number of favorable cases to event C=2
If the two events A and B are independent then
Therefore, A and B are independent
Therefore, B and C are independent
Therefore, A and C are independent.
Hence, A, B and C are pairwise independent.