The possibility of flipping heads is 1 in 2 (1/2)
the possibility of pulling a black card is 26 in 52 (26/52) which equals 1 in 2 (1/2)
multiply those together and you get 1 in 4, 1/4, or a 25%
Hey there! I'm happy to help!
To find the distance between two points, you square the difference of the x-values and square the difference of the y-values, add them, and then you square root it!
First, we'll add our two x-values.
-6-0= -6
We square it, which means to multiply it by itself.
-6(-6)=36 (If you multiply an even number of negative numbers, your answer is positive. Since we have two negative numbers, we get positive 36)
Now, we do the same with the y-values.
-2-(-1)=-1 (two negatives make it a plus, as in minus minus 1 is plus one.)
We square it.
-1(-1)=1
Now, we add these x and y value differences.
36+1=37
Now, we find the square root using a calculator.
√37≈6.08
Have a wonderful day!
Maximum number of packets = 8
16 ÷ 8 = 2
There are 2 pencils in each packet.
24÷8 = 3
There are 3 erasers in each bag.
Rosy can have a maximum of 8 packets. Each packet has 2 pencils and 3 erasers.
Answer:
probability that contractor 1,2 and 3 win is 33%,50% and 17% respectively
Step-by-step explanation:
assuming that there are no other contractors then:
probability that 1 , 2 or 3 win = 1
denoting as X= probability that contractor 3 wins , then assuming that only one wins , we have
probability that 1 , 2 or 3 win = 1
probability that contractor 1 wins + probability that contractor 2 wins + probability that contractor 3 wins = 1
2*P(X) + 3*P(X) + P(X) = 1
6*P(X) = 1
P(X) =1/6
then
-probability that contractor 1 wins = 2/6 (33%)
-probability that contractor 3 wins = 3/6 (50%)
-probability that contractor 3 wins = 1/6 (17%)
