Answer:
P(inside larger square and outside smaller) = 
Step-by-step explanation:
Probability is the result of the division of the number of possible outcome by the number of an event.
In the question, for a point chosen, the point can be in the small square only or in the area or region between the small square and the big square as such,
Area of larger square = area of region between both squares + area of smaller square
Where the area of a square is S × S where S is the side of a square
Area of larger square = 10 × 10
= 100 cm square
Area of smaller square = 7 × 7
= 49 cm square
Area of the region between both squares
= 100 - 49
= 51 cm square
The probability that a dot selected is inside the larger square and outside the smaller is
P(inside larger square and outside smaller) = Area of region between both square/ Area of larger square
P(inside larger square and outside smaller) = 
Answer:
89/35 = 2 and 19/35
Step-by-step explanation:
Answer:
A
Step-by-step explanation:
Hey there!
D is the answer.
I was thinking it might be B but no one said the lines crossed each other.
Hope this helps, Jesus loves you!
Answer:
And we can find this probability with the normal standard distirbution or excel and we got:
Step-by-step explanation:
Previous concepts
Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".
The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".
Solution to the problem
Let X the random variable that represent the lenghts of a population, and for this case we know the distribution for X is given by:
Where
and
We are interested on this probability
And the best way to solve this problem is using the normal standard distribution and the z score given by:
If we apply this formula to our probability we got this:
And we can find this probability with the normal standard distirbution or excel and we got: