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3 years ago

Sin60+ tan60÷ cos60+ sec60

Mathematics

2 answers:

AURORKA [14]3 years ago

6 0

Answer for this problem: 6.33012701

siniylev [52]3 years ago

4 0

Answer:

5.196152423

Step-by-step explanation:

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The gas mileage for a certain model of car is known to have a standard deviation of 6 mi/gallon. A simple random sample of 36 ca

xxTIMURxx [149]

The 98% confidence interval for the mean gas mileage for this car model is (26.07,30.73).

Confidence intervals are defined as a range of values with a known chance that a parameter's value falls inside them.

The confidence interval of statistical data is computed using the formula:

$(\overline{x} - Z\frac{\sigma }{n},\overline{x} + Z\frac{\sigma }{n})$

where $\overline{x}$ is the mean, Z is the Z-score corresponding to the confidence interval, σ is the standard deviation, and n is the sample size.

In the question, the sample size (n) = 36, the mean of the sample ( $\overline{x}$ ) = 28.4 mi/gallon, the standard deviation (σ) = 6 mi/gallon.

The confidence interval given to us is 98%.

Z-score corresponding to this (Z) = 2.33.

Thus, the confidence interval can be calculated as:

(28.4 - 2.33{6/√36},28.4 + 2.33{6/√36})

= (28.4 - 2.33,28.4 + 2.33)

= (26.07,30.73).

Thus, the 98% confidence interval for the mean gas mileage for this car model is (26.07,30.73).

Learn more about constructing confidence intervals at

brainly.com/question/17030704

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5 0

2 years ago

Sin(x2 y2 da r , where r is the region in the first quadrant between the circles with center the origin and radii 1 and 5

Rudik [331]

I assume there's a plus sign missing above...

Convert to polar coordinates, using

$\begin{cases}x(r,\theta)=r\cos\theta\\y(r,\theta)=r\sin\theta\end{cases}$

Then the Jacobian is

$\dfrac{\partial(x,y)}{\partial(r,\theta)}=\begin{vmatrix}x_r&y_r\\x_\theta&y_\theta\end{vmatrix}=\begin{vmatrix}\cos\theta&\sin\theta\\r\sin\theta&-r\cos\theta\end{vmatrix}=-r$

Then

$\mathrm dA=\mathrm dx\,\mathrm dy=|-r|\,\mathrm dr\,\mathrm d\theta=r\,\mathrm dr\,\mathrm d\theta$

so the integral can be written as

$\displaystyle\iint_R\sin(x^2+y^2)\,\mathrm dA=\int_0^{\pi/2}\int_1^5r\sin(r^2)\,\mathrm dr\,\mathrm d\theta$

Let $s=r^2$ , so that $\dfrac{\mathrm ds}2=r\,\mathrm dr$ .

$\displaystyle\frac12\int_0^{\pi/2}\int_1^{25}\sin s\,\mathrm ds\,\mathrm d\theta=-\frac12(\cos25-\cos1)\int_0^{\pi/2}\mathrm d\theta=\frac\pi4(\cos1-\cos25)$

3 0

3 years ago

Please anyone help anyway you can

umka21 [38]

D=2R
3.14x10=31.4
This app won't let me do short answer

6 0

3 years ago

Plzzzzzzzzzz helpppppppp

Minchanka [31]

Answer:

i'd say do it with division what equals 31? im not going to say the staright up answer

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7 0

3 years ago

What number must each side of the equation

zysi [14]

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7 0

3 years ago