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Mathematics

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Vesnalui [34]2 years ago

5 0

Answer:

i dont have it the answer ofvthis

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The lovin lemonade company sells a 4 gallon jug of lemonade for $24 the sweet and sour company sells an eight pack of 1 quart bo

lbvjy [14]

One way to compare is to find the price per gallon.
$24 for 4 gallons = 24÷4 = $6 per gallon

8 pack of 1 qt bottle give you 2 gallons (4qts= 1 gallon) So you get 2 gallons for $16
$16 ÷ 2 = $8.00 per gallon. Sweet and Sour has the higher unit price.
Even if we compare the price per quart we will get the same answer as to who is selling it at the higher unit price.
4gal for $24 = 16 quarts for $24 ( 1 gallon = 4 qts)
$24 ÷ 16 = $1.50 each (1 $\frac{1}2}$ )
vs.
8 quarts for $16 $16 ÷ 8 = $2.00 per qt. Sweet and sour still has the higher unit price

7 0

3 years ago

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A survey of 90 men found that an average amount spent on St. Patrick's day of $55 with a standard deviation of $18. A similar su

dem82 [27]

Answer:

The value of the test statistic is 4.70.

Step-by-step explanation:

The hypothesis for this test can be defined as follows:

H₀: Men do not spend more than women on St. Patrick's day, i.e. μ₁ = μ₂.

Hₐ: Men spend more than women on St. Patrick's day, i.e. μ₁ > μ₂.

The population standard deviations are not known.

So a t-distribution will be used to perform the test.

The test statistic for the test of difference between mean is:

$t=\frac{\bar x_{1}-\bar x_{2}}{\sqrt{\frac{s^{2}_{1}}{n_{1}}+\frac{s^{2}_{2}}{n_{2}}} }$

Given:

$\bar x_{1}=55\\s_{1}=18\\n_{1}=90\\\bar x_{1}=44\\s_{1}=16\\n_{1}=86$

Compute the value of the test statistic as follows:

$t=\frac{\bar x_{1}-\bar x_{2}}{\sqrt{\frac{s^{2}_{1}}{n_{1}}+\frac{s^{2}_{2}}{n_{2}}} }=\frac{55-44}{\sqrt{\frac{15^{2}}{90}+\frac{16^{2}}{86} }}=4.70$