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siniylev [52]
2 years ago
10

Find the area of the shape shown below:

Mathematics
1 answer:
Naddika [18.5K]2 years ago
3 0

Answer:

80

Step-by-step explanation:

3.5*2*2*2*2*5=280

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11 th term of the following geometric sequence.<br> 10,50,250,1250
Natasha2012 [34]

Answer:

97,656,250

Step-by-step explanation:

The first term, a(1), is 10.  The next is 5 times greater.  And so on.  Thus, the common ratio is 5, and the general formula for this sequence is

a(n) = a(1)*5^(n -1).

Therefore,

a(11) = 10*5^(11 - 1) = 10*5^10  =  97,656,250

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A​ person's blood pressure is monitored by taking 4 readings daily. The probability distribution of his reading had a mean of 13
ss7ja [257]

Answer:

a) Mean = 133, Standard deviation = 2.5

b) Normal distribution

c) 0.0026

Step-by-step explanation:

We are given the following in the question:

Sample size, n = 4

Mean = 133

Standard deviation = 5

a) Mean and the standard deviation of the sampling distribution of the sample mean for the four observations each day.

The sampling distribution has a mean equal to the population mean

\bar{x} = \mu = 133

The standard deviation of the sampling distribution is given by:

\sigma_s = \dfrac{\sigma}{\sqrt{n}} = \dfrac{5}{\sqrt{4}} = 2.5

b) Shape of the sampling​ distribution

Central limit theorem:

When a large sample is drawn from a normal distribution, then the distribution of sample means approaches a normal distribution.

Since the distribution is normal,  the sampling distribution of the sample mean will be bell shaped and follow a normal distribution.

c) P(sample mean exceeds 140)

P( x > 140) = P( z > \displaystyle\frac{140 - 133}{2.5}) = P(z > 2.8)

= 1 - P(z \leq 2.8)

Calculation the value from standard normal z table, we have,  

P(x > 140) = 1 - 0.9974 = 0.0026

0.0026 is the probability that the sample mean exceeds 140.

6 0
2 years ago
Sqrt2y-5+8=4 what Is the root
alexandr402 [8]

Answer:

The root of \sqrt{2y-5} +8 = 4 is 10.5.

Step-by-step explanation:

Given that,

\sqrt{2y-5} +8 = 4

As we have a square root term along with a single term on left side. We will move the single term on right side.

\sqrt{2y-5}  = 4-8

\sqrt{2y-5}  = -4

Taking the square on both sides, we get

(\sqrt{2y-5})^2  = (-4)^2

Square will cancel the impact of square root, therefore:

({2y-5})  = 16

2y = 16+5

2y = 21

y = \frac{21}{2}

y = 10.5

Therefore, the root of \sqrt{2y-5} +8 = 4 is 10.5.  

5 0
3 years ago
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