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2 years ago

Been having this question for a while and this app wont help

Mathematics

1 answer:

Anarel [89]2 years ago

8 0

The answer is B

When there is a solid point that means it is included in the graph, so you'd use a greater/less than or equal to symbol (the one with a line under). If it's an unfilled point then it means that it is not included in the graph, so you'd use a greater/less than sign.

The x² equation is less than 2 while the linear equation is greater than or equal to 2.

We know it's the x² equation that is less than two because it has a curve in it.

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Determine the horizontal vertical and slant asymptote y=x^2+2x-3/x-7

lilavasa [31]

Answer:

<h2>A.Vertical:x=7</h2><h2>Slant:y=x+9</h2>

Step-by-step explanation:

$f(x)=\dfrac{x^2+2x-3}{x-7}\\\\vertical\ asymptote:\\\\x-7=0\qquad\text{add 7 to both sides}\\\\\boxed{x=7}\\\\horizontal\ asymptote:\\\\\lim\limits_{x\to\pm\infty}\dfrac{x^2+2x-3}{x-7}=\lim\limits_{x\to\pm\infty}\dfrac{x^2\left(1+\frac{2}{x}-\frac{3}{x^2}\right)}{x\left(1-\frac{7}{x}\right)}=\lim\limits_{x\to\pm\infty}\dfrac{x\left(1+\frac{2}{x}-\frac{3}{x^2}\right)}{1-\frac{7}{x}}=\pm\infty\\\\\boxed{not\ exist}$

$slant\ asymptote:\\\\y=ax+b\\\\a=\lim\limits_{x\to\pm\infty}\dfrac{f(x)}{x}\\\\b=\lim\limits_{x\to\pm\infty}(f(x)-ax)\\\\a=\lim\limits_{x\to\pm\infty}\dfrac{\frac{x^2+2x-3}{x-7}}{x}=\lim\limits_{x\to\pm\infty}\dfrac{x^2+2x-3}{x(x-7)}=\lim\limits_{x\to\pm\infty}\dfrac{x^2+2x-3}{x^2-7x}\\\\=\lim\limits_{x\to\pm\infty}\dfrac{x^2\left(1+\frac{2}{x}-\frac{3}{x^2}\right)}{x^2\left(1-\frac{7}{x}\right)}=\lim\limits_{x\to\pm\infty}\dfrac{1+\frac{2}{x}-\frac{3}{x^2}}{1-\frac{7}{x}}=\dfrac{1}{1}=1$

$b=\lim\limits_{x\to\pm\infty}\left(\dfrac{x^2+2x-3}{x-7}-1x\right)=\lim\limits_{x\to\pm\infty}\left(\dfrac{x^2+2x-3}{x-7}-\dfrac{x(x-7)}{x-7}\right)\\\\=\lim\limits_{x\to\pm\infty}\left(\dfrac{x^2+2x-3}{x-7}-\dfrac{x^2-7x}{x-7}\right)=\lim\limits_{x\to\pm\infty}\dfrac{x^2+2x-3-(x^2-7x)}{x-7}\\\\=\lim\limits_{x\to\pm\infty}\dfrac{x^2+2x-3-x^2+7x}{x-7}=\lim\limits_{x\to\pm\infty}\dfrac{9x-3}{x-7}=\lim\limits_{x\to\pm\infty}\dfrac{x\left(9-\frac{3}{x}\right)}{x\left(1-\frac{7}{x}\right)}$

$=\lim\limits_{x\to\pm\infty}\dfrac{9-\frac{3}{x}}{1-\frac{7}{x}}=\dfrac{9}{1}=9\\\\\boxed{y=1x+9}$

8 0

3 years ago

What is the end behavior of the function <img src="https://tex.z-dn.net/?f=f%28x%29%3D-%5Cfrac%7B1%7D%7B4%7D%20x%5E2" id="TexFor

Anarel [89]

Answer:

Option A will be your answer

Step-by-step explanation:

hope it helps ..

have a great day!!

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3 years ago

Find slope of line (1,2) and (2,5) Write equation and final answer

sdas [7]

Equation: y = 3x
Final Answer: 3

3 0

3 years ago

Sharon and Sue are making muffins. Sharon uses 3 cups of milk, and Sue uses 1 pint of milk. Who uses the greater amount of milk?

stiks02 [169]

answer:

Sharon used more milk because 3 cups equal 1.5 (one and a half) pints.

Detailed answer:

1 cup equals 0.5 pints or half of a pint. So if you take 0.5 and multiply it by 3 you get 1.5 and that is the amount of pints that Sharon uses but Sue uses 1 pint or 2 cups. so 1.5 pints is grater than 1 pint by 0.5

(sorry if this was not so clear i am not that good at explaining things, also i hope this helps and you get a good score on whatever you are doing.)

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3 years ago

Please Help me!!! The question is: Which graph shows the solution to y > x – 8?

FinnZ [79.3K]

Answer:

the answer is B

Step-by-step explanation:

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