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2 years ago

Can u guys help me on #24

Mathematics

1 answer:

lora16 [44]2 years ago

7 0

56.5ft x 17ft x 1ft = 960.5ft^3.

The question wants the answer in ft^3. One of the measurements is given as 13 inches but that converts to 1ft. And with the volume formula for rectangles is widthxlenghtxheight. Plug in the numbers.

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Consider the rule y = 5x + 7.

maksim [4K]

Answer:

see below

Step-by-step explanation:

Consider the rule y = 5x + 7.

a. How many tiles are in Figure 0?

In figure 0, we let x=0

y = 5*0+7 = 0+7 = 7

b. Which figure has 37 tiles?

This means y = 37

37 = 5x+7

Subtract 7 from each side

37-7 = 5x+7-7

30 = 5x

Divide by 5

30/5 = 5x/5

6 =x

Figure 6 has 37 tiles

c. In the equation y = mx + b, what do the letters m and b represent?

m is the slope or how much it is increasing each time x increases by 1 and b is how much we start with when x =0

5 0

3 years ago

If the number of types of massages is represented by 4x + 3 and the number of types of manicures is represented by -6x + 5 and t

svetlana [45]

Answer:

Step-by-step explanation:

If the number of types of massages is represented by 4x + 3 and the number of types of manicures is represented by -6x + 5 and the number of types of pedicures is represented by 8x - 7, what is the expression for the total number of services they have to choose from?

6 0

2 years ago

Please help it is easy. i just dont get it. you get extra points for this question

Igoryamba

2,3,7,and 5 are the factors

7 0

2 years ago

your bedroom is in the shape of a square that is 12 feet long on each side. Will a circular rug with a circumference of 40.82 fe

kotegsom [21]

Circumference = PI * diameter
diameter = Circumference / PI
diameter = 40.82 / 3.14159265
diameter = 12.9934095689 
Basically, the rug is roughly 1 foot wider than the room.

7 0

2 years ago

The length of a rectangle is 59 inches greater than twice the width. If the diagonal is 2 inches more than the length, find the

Paul [167]

So.. hmm notice the picture here

we know the length is 59 more than twice the width,
twice the width, 2 * w, or 2w
59 more than that
2w + 59

we also know that, whatever that is, the diagonal of it is,
2 more inches than that, or
(2w + 59) + 2

now.. use the pythagorean theorem
$\bf c^2=a^2+b^2\implies \qquad 
\begin{cases}
a=2w+59\\
b=w\\
c=(2w+59)+2\to 2w+61
\end{cases}
\\\\\\
(2w+61)^2=(2w+59)^2+(w)^2
\\ \qquad\qquad \uparrow\qquad \qquad\qquad \qquad \uparrow \\
\textit{expand using binomial theorem, or FOIL}$

you'd end up with a quadratic, after simplifying, solve for "w"

7 0

2 years ago