2 years ago

Solve for x. x^2+12x<-11

Mathematics

1 answer:

sineoko [7]2 years ago

5 0

x²+12x<-11

x²+12x+11<0

x²+12x+11=0

(x+11)(x+1)=0

x+11=0 x+1=0

x= -11 x= -1

Solution: ] -11 , -1 [

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Hitman42 [59]

Answer: L = 20.25

<u>Step-by-step explanation:</u>

$T=2\pi \sqrt{\dfrac{L}{32}}$

Given: T = 5, π = 22/7

$5=2\bigg(\dfrac{22}{7}\bigg)\sqrt{\dfrac{L}{32}}\\\\\\\dfrac{5}{2}\bigg(\dfrac{7}{22}\bigg)=\sqrt{\dfrac{L}{32}}\\\\\\\dfrac{35}{44}=\sqrt{\dfrac{L}{32}}\\\\\\\bigg(\dfrac{35}{44}\bigg)^2=\bigg(\sqrt{\dfrac{L}{32}}\bigg)^2\\\\\\\bigg(\dfrac{35}{44}\bigg)^2=\dfrac{L}{32}\\\\\\32\bigg(\dfrac{35}{44}\bigg)^2=L\\\\\\\large\boxed{20.25=L}$