P(B) = 8/12
P(R | B) = 4/11
P(B ∩ R) = 8/33
The probability that the first ball chosen is black and the second ball chosen is red is about 24% percent
<em><u>Solution:</u></em>
<em><u>The probability is given as:</u></em>

Given that,
A box contains four red balls and eight black balls
Red = 4
Black = 8
Total number of possible outcomes = 12
Let event B be choosing a black ball first and event R be choosing a red ball second.
<h3><u>Find P(B)</u></h3>

<h3><u>Find P(B n R)</u></h3>

<h3><u>Find </u><u>
P(R | B)</u></h3><h3>

</h3>
<em><u>The probability that the first ball chosen is black and the second ball chosen is red is about percent</u></em>

Thus the probability that the first ball chosen is black and the second ball chosen is red is about 24% percent
The answer is A. The square root of 100 is ten because ten times ten is 100.
That means one whole is cut into 8 parts, and one of those eight parts is considered to be one-eighth of a whole
{think about it like a pizza with 8 slices]
Previous taxable income - 30,000
Less: Deductions - 5,000 + 350 = 5,350
New taxable income - 24,650
Multiply: Marginal tax rate - 15%
Tax - 3,697.50
1.) She lowered her taxable income by 5,350.
2.) Her taxable income now is 24,650.
3.) Her taxable income falls under the income range of 8,375 - 34,000, so her marginal tax rate is 15%.
4.) She will have to pay 3,697.50 for her tax.