How do you write a linear function

Mathematics

1 answer:

bazaltina [42]3 years ago

8 0

1. Start out with y=mx+b. 'm' is the slope and 'b' is the y intercept.

2. Find where the line hits the y-axis on the graph. This will be your Y-Intercept.

3. Find where your line hits the X-axis. Now, count up or down from the x-axis until you get to the height of the y-point. now count across. Down/Up Divided by Across. This is your slope.

For Example, say that the line hits the Y-Axis at 4, and the line hits the X-Axis at -8. Count up from -8 till you get to the height of 4. It is 4. Now count across from that height. It is 8. Now, just put 4 on top of 8, to get 4/8. Simplify to 1/2. That is your slope. And since the line hit the Y-Axis at 4, 4 would be your Y-Intercept. Your final formula would be:

y=1/2x+4

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Which graph represents the solution to the system of inequalities below?

Reika [66]

Answer:

The correct option is;

Step-by-step explanation:

The given system of inequalities are;

5·x - 4·y > 4...(1)

x + y < 2...(2)

Representing both inequalities as a function of "y", gives;

For, 5·x - 4·y > 4...(1), we have;

-4·y > 4 - 5·x

y < 4/(-4) - 5·x/(-4)

∴ y < 5·x/4 - 1

For x + y < 2...(2), we have;

y < 2 - x

Therefore, y is less than the values given by the equation of the straight line equalities, and the feasible region is given by the common region under both dashed lines representing both inequalities as shown in the attached diagram created using Microsoft Excel

The correct option is therefore, B.