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4 years ago

I need help with this question fast plz help me

Mathematics

2 answers:

tekilochka [14]4 years ago

4 0

Answer:

Answer: Your answer is -13.37500. Hope this helps!

Step-by-step explanation:

Nonamiya [84]4 years ago

3 0

Answer: Your answer is -13.37500. Hope this helps!

Step-by-step explanation:

You might be interested in

At a carnival, 700 tickets were sold for a total

Diano4ka-milaya [45]

Answer:

The adult tickets are 400 and the children tickets are 300.

Step-by-step explanation:

Given:

At a carnival, 700 tickets were sold for a total amount of $5500. An adult ticket cost $10 and a children's ticket cost $5.

Now, to find the number of adult tickets and the number of children's tickets sold.

Let the number of adult tickets be $x.$

And let the number of children tickets be $y.$

So, the total number of tickets sold:

$x+y=700\\\\y=700-x\ \ \ ....(1)$

Now, the total amount of tickets:

$x(10)+y(5)=5500$

Substituting the value of $y$ from equation (1):

$x(10)+(700-x)(5)=5500\\\\10x+3500-5x=5500\\\\5x+3500=5500$

Subtracting both sides by 3500 we get:

$5x=2000$

Dividing boths sides by 5 we get:

$x=400.$

The number of adult tickets = 400.

Now, substituting the value of $x$ in equation (1) we get:

$y=700-x\\\\y=700-400\\\\y=300.$

The number of children tickets = 300.

Therefore, the adult tickets are 400 and the children tickets are 300.

8 0

4 years ago

WhAt is .51 rounded of to the nearest cent

statuscvo [17]

I think its .50 but I could be wrong

8 0

3 years ago

Exhibit 6-2 the weight of football players is normally distributed with a mean of 200 pounds and a standard deviation of 25 poun

Evgen [1.6K]

The question is asking for the lower bound of the 95% two tailed Confidence interval of the normally distributed population.

95% C.I. is given by 200 + or - 1.96(25) = 200 + or - 49 = (151, 249)
Therefore, the minimum weight of the middle 95% of players is 151 pounds.

5 0

3 years ago

The charitable foundation for a large metropolitan hospital is conducting a study to characterize its donor base. In the past, m

pentagon [3]

Answer:

Step-by-step explanation:

a) We would set up the hypothesis test. This is a test of a single population mean since we are dealing with mean

For the null hypothesis,

H0: µ equal to 100000

For the alternative hypothesis,

H1: µ greater than 100000

This is a right tailed test

Since the population standard deviation is nit given, the distribution is a student's t.

Since n = 200

Degrees of freedom, df = n - 1 = 200 - 1 = 199

t = (x - µ)/(s/√n)

Where

x = sample mean = 103157

µ = population mean = 100000

s = samples standard deviation = 27498

t = (103157 - 100000)/(27498/√200) = 1.62

We would determine the p value using the t test calculator.

p = 0.053

Alpha = 10% = 0.1

Since alpha, 0.1 > than the p value, 0.053, then

b) At the 10% significant level, the p-value/statistics is 0.053, so we should not reject the null hypothesis.

c) Hence, we may conclude that the average has not increased and the probability that our conclusion is correct is at least 90 percent.

8 0

3 years ago

Someone help please so confused

8_murik_8 [283]

Answer:126.75 pi

Step-by-step explanation: A= 3/4 X 13^2 pi

7 0

4 years ago