Answer:
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1. energy and air
2.
Answer:
1. Speed and velocity both involve a numeric rate describing the distance traveled by a body in a unit of time. However, speed describes the rate of a body traveling in any direction in a unit of time, while velocity describes the rate of a body traveling in a particular direction in a unit of time.
2. Answers may vary, but should resemble the following:
Average velocity explains the velocity the body traveled overall, not taking into consideration each spot in the trip. If a car moves at 65 km/h on average, it may have slowed down for some parts and sped up for others. Overall though, it would have made a certain distance of travel within a specified unit of time that totals the average velocity of 65 km/h.
Instantaneous velocity explains the velocity of a body at a particular instant of the trip. The instantaneous velocity of a car stopped at a stop sign would be 0 m/s even if it was moving before and will continue to move after this stop. The velocity at that particular instant is the instantaneous velocity.
Uniform velocity is when the distance being covered is changing uniformly with time. For example, if a car moves 20 km every 30 minutes and continues to do so in the same direction, it's traveling with a uniform velocity.
3. a=v2−v1t
a=20 m/s−60 m/s6 s
a=−406
a = –6.7 m/s2
4. v2 = v1 + at
v2 = 14 m/s + (3 m/s2 × 6 s)
v2 = 14 + 18
v2 = 32 m/s
5. v=st
v=375 km5 h
v = 75 km/h
6. First, convert the minutes to seconds. Since there are 60 seconds in one minute, multiply:
60 × 15 (minutes) = 900 seconds
s = v × t
s = 6 m/s × 900 s
s = 5,400 m
7. t=sv
t=80 km35 km/hr
t = 2.29 hr
8. a=v2−v1t
a=50 m/s−15 m/s4 s
a=35 m/s4 s
a = 8.75 m/s2
9. vav=v1+v22
vav=15 m/s+50 m/s2
vav=65 m/s2
vav = 32.5 m/s
10. a=v2−v1t
a=0 m/s−11.5 m/s3.5 s
a = –3.29 m/s2
Explanation:
a) de Broglie wavelength of a 4-MeV proton: 14.3 fm
b) de Broglie wavelength of a 40-GeV electron: 0.031 fm
Explanation:
a)
The de Broglie wavelength of an object is given by
(1)
where
h is the Planck constant
p is the momentum of the particle
Here we want to find the de Broglie wavelength of a 4-MeV proton. The rest of mass of the proton in MeV is
And since 
, this means that the proton is non-relativistic. So its kinetic energy is related to its momentum by
which means
where
![E=4 MeV \cdot 10^6 eV/MeV \cdot 1.6\cdot 10^{-19] J/eV=6.4\cdot 10^{-13} J](https://tex.z-dn.net/?f=E%3D4%20MeV%20%5Ccdot%2010%5E6%20eV%2FMeV%20%5Ccdot%201.6%5Ccdot%2010%5E%7B-19%5D%20J%2FeV%3D6.4%5Ccdot%2010%5E%7B-13%7D%20J)
is the kinetic energy
is the proton mass
Substituting, we find
b)
In this case, the electron has kinetic energy of 40 GeV, while the rest mass of an electron is
Since 
, the electron is ultra-relativistic: so we can rewrite its energy as
The equation (1) can also be rewritten as
where c is the speed of light. The quantity at the denominator is the energy, so
where:
is the energy of the electron
And substituting, we find:
Learn more about de Broglie wavelength:
brainly.com/question/7047430
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a. <span>FM GmMmr2
</span>= 6.67 x 10-11N.m2kg27 .35 x 1022 kg 70 kg 3.78 x 108 m2
<span>= 2.40 x 10-3 N
b. </span><span>FE GmEmr2
= 6.67 x 10-11 N.m2kg 25 .97 x 1034 kg (70kg) 6.38 x 106 m2
=685 N
FMFE 2.40 x 10-3N685 N= 0.0004%</span>
A) We can use the equation of motion:
2as = v² - u²
s = (12² - (-6)²) / 2 x 4
s = 13.5 m
b) We calculate the time over which this displacement occurred using:
v = u + at
t = (12 - -6)/4
t = 4.5 seconds
Assuming the average speed equal to:
(12 + 6) /2 = 9 m/s
average speed = total distance/total time
total distance = 9 x 4.5
= 40.5 m
