What is the value of x?

Guys pls kindly help me with this one I will brainlest the one with a serious answer please I need it right now this is rush ple

Galina-37 [17]

Hey there :)

An exact answer cannot be given as it requires to reseach about banks and co-operatives in your locality. However, I can give you a hint.

Research banks or cooperatives in your location that has the greatest percentage in terms of investment or savings.

Let's say, for example, Bank ABC has 5% annual simple interest in their Savings Account.

If you invest your entire money 100,000 pesos at Bank ABC with 5% annual interest for 20 years, you will earn an interest of:

$Interest = Principal \times Rate \times Time$

$= > Interest =100000 \times 0.05 \times 20yrs$

$= > Interest = 100000$

Hence, after investing at Bank ABC for 20 years, you will earn 100,000 pesos on top of your principal/invested amount that is 100,000 pesos. Your money will become 200,000 pesos now.

So, with this, find a bank/cooperative that has the highest return rate in your location. Once you have decided bank/cooperative, research further with regards to the background of the company, other services offered, application requirements, etc.

~ Benjemin360

4 0

3 years ago

Can someone please help me

Georgia [21]

It’s 1/2 because every time the x variable goes up 1, the y variable goes up 2

4 0

4 years ago

Read 2 more answers

A balloon is blowing up at a constant rate of 9 cubic centimeters per second. When the volume of the balloon is 2048/3 pi cubic

jekas [21]

Answer:

$\displaystyle \frac{dr}{dt}\approx 0,0112\ cm/sec$

Step-by-step explanation:

Rates of Change as Derivatives

If some variable V is a function of another variable r, we can compute the rate of change of one with respect to the other as the first derivative of V, or

$\displaystyle V'=\frac{dV}{dr}$

The volume of a sphere of radius r is

$\displaystyle V=\frac{4}{3}\pi r^3$

The volume of the balloon is growing at a rate of $9\ cm^3/sec$ . This can be written as

$\displaystyle \frac{dV}{dt}=9$

We need to compute the rate of change of the radius. Note that both the volume and the radius are functions of time, so we need to use the chain rule. Differentiating the volume with respect to t, we get

$\displaystyle \frac{dV}{dt}=\displaystyle \frac{dV}{dr}\displaystyle \frac{dr}{dt}$