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AysviL [449]
3 years ago
13

​​ What is the area of a rectangle with vertices at ​ (−4, 0) ​, ​ (−3, 1) ​ , (0, −2) , and (−1, −3) ? Enter your answer in the

box. Do not round any side lengths.
Mathematics
1 answer:
Mkey [24]3 years ago
6 0
First, find the distance between (-4, 0) and (-1, -3) by using the distance formula, you will get the √18
second, find the distance between (-4, 0) and (-3, 1), the result is √2
so the area is the √18*√2=6

Please refer to this website for the distance formula:
http://www.mathwarehouse.com/algebra/distance_formula/index.php

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Tema [17]

Answer:

y= -5/4

Step-by-step explanation:

download a app called math papa. it's a great cheat cheat for these types of problems

8 0
3 years ago
A positive integer is twice another.the sum of the reciprocal of the two positive integer is 3/14. Find the integers
icang [17]

Answer:

\huge\boxed{14\ \text{and}\ 7}

Step-by-step explanation:

n,\ m-\text{positive integer}\\\\n=2m-\text{a positive integer is twice another}\\\\\dfrac{1}{n}+\dfrac{1}{m}=\dfrac{3}{14}-\text{the sum of the reciprocal of the two positive integer is }\ \dfrac{3}{14}\\\\\text{We have the system of equations:}\\\\\left\{\begin{array}{ccc}n=2m&(1)\\\dfrac{1}{n}+\dfrac{1}{m}=\dfrac{3}{14}&(2)\end{array}\right

\text{Substitute (1) to (2):}\\\\\dfrac{1}{2m}+\dfrac{1}{m}=\dfrac{3}{14}\\\\\dfrac{1}{2m}+\dfrac{1\cdot2}{m\cdot2}=\dfrac{3}{14}\\\\\dfrac{1}{2m}+\dfrac{2}{2m}=\dfrac{3}{14}\\\\\dfrac{1+2}{2m}=\dfrac{3}{14}\\\\\dfrac{3}{2m}=\dfrac{3}{14}\Rightarrow2m=14\qquad\text{divide both sides by 2}\\\\\dfrac{2m}{2}=\dfrac{14}{2}\\\\\boxed{m=7}

\text{Substitute it to (1):}\\\\n=2\cdot7\\\\\boxed{n=14}

8 0
3 years ago
How would i solvd this problem as sn improper fraction 2 1/8
zmey [24]
17/8..........................................
7 0
3 years ago
Read 2 more answers
A triangle has the coordinates
fiasKO [112]

Answer:

coordinates of its image

A' = ( -4, -1)

B' =( -3, -3)

C' = ( 0, 2)

Step-by-step explanation:

Reflect in y-axis means mirror it's points in the y -axis.

This means that the x coordinate of each point, changes only. Any mirrored point in the y-axis, will change only, by multiplying the x-coordinate by -1.

(Remember, zero multiplied by -1 remains 0).

Given are these points A, B, and C.

A = (4, -1)

B = (3,-3)

C = (0, 2)

After mirroring in the y- axis you get:

A' = ( -4, -1)

B' =( -3, -3)

C' = ( 0, 2)

8 0
3 years ago
Can someone help me find my error
AfilCa [17]

Answer:

try dividing 102 by 4 then after that make the length a lil bit bigger than the width but make sure it still equals 102

Step-by-step explanation:

mark me brainleist and ill give solution

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