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AysviL [449]
3 years ago
13

​​ What is the area of a rectangle with vertices at ​ (−4, 0) ​, ​ (−3, 1) ​ , (0, −2) , and (−1, −3) ? Enter your answer in the

box. Do not round any side lengths.
Mathematics
1 answer:
Mkey [24]3 years ago
6 0
First, find the distance between (-4, 0) and (-1, -3) by using the distance formula, you will get the √18
second, find the distance between (-4, 0) and (-3, 1), the result is √2
so the area is the √18*√2=6

Please refer to this website for the distance formula:
http://www.mathwarehouse.com/algebra/distance_formula/index.php

You might be interested in
If c is the curve given by \mathbf{r} \left( t \right = \left( 1 5 \sin t \right \mathbf{i} \left( 1 3 \sin^{2} t \right \mathbf
jonny [76]
With the curve C parameterized by

C:\mathbf r(t)=\underbrace{15\sin t}_{x(t)}\,\mathbf i+\underbrace{13\sin^2t}_{y(t)}\,\mathbf j+\underbrace{12\sin^3t}_{z(t)}\,\mathbf k

with 0\le t\le\dfrac\pi2, and given the vector field

\mathbf f(x,y,z)=x\,\mathbf i+y\,\mathbf j+z\,\mathbf k

the work done by \mathbf f on a particle moving on along C is given by the line integral

\displaystyle\int_C\mathbf f\cdot\mathrm d\mathbf r=\int\limits_{t=0}^{t=\pi/2}\mathbf f(x(t),y(t),z(t))\cdot\frac{\mathrm d\mathbf r(t)}{\mathrm dt}\,\mathrm dt

where

\mathrm d\mathbf r=(15\cos t\,\mathbf i+26\sin t\cos t\,\mathbf j+36\sin^2t\cos t\,\mathbf k)\,\mathrm dt

The integral is then

\displaystyle\int_0^{\pi/2}(15\sin t\,\mathbf i+13\sin^2t\,\mathbf j+12\sin^3t\,\mathbf k)\cdot(15\cos t\,\mathbf i+13\sin2t\,\mathbf j+18\sin t\sin2t\,\mathbf k)\,\mathrm dt
=\displaystyle\int_0^{\pi/2}(432\sin^5t\cos t+338\sin^3t\cos t+225\sin t\cos t
=269
6 0
3 years ago
Please help ASAP, giving brainliest!
scoundrel [369]

Answer:no

Step-by-step explanation:

Because you have two -2 in the x slots , if you see an number more than once it is no longer a function.

7 0
3 years ago
Is this equation true? 1.2(2x-5)=2/5(2x-15)+1.6x
kobusy [5.1K]

Answer:

no, there is an infatuate amount of solutions

Step-by-step explanation:

1.2(2x-5)=2/5(2x-15)+1.6x

2.4x -6 = .8x -6 +1.6

2.4 -6 = 2.4-6

0=0 ( infatuate)

7 0
3 years ago
How do you write 12/75 as a decimal
sammy [17]
\frac{12}{75} = \frac{4\times 3}{25\times 3} = \frac{4}{25}= \frac{4\times 4}{25\times 4}  = \frac{16}{100} =\boxed {0.16}
6 0
3 years ago
Help ASAP!!!!!!!!!!!!!!!​
Stells [14]

Answer: 4.0 * 10^0 kg = 4.0 kg essentially

Step-by-step explanation:

No need to convert these to numbers...

Weight of 1 bee: 1 * 10^-4 = (0.0001 kg)

Number of bees: 4 * 10^4 = (40000 bees)

(1 * 10^-4) * (4 * 10^4) =

(1 * 4) * (10^-4 * 10^4) =

(10^0 because when multiply exponential numbers, you add the exponents)

4 * 10^0 =

4 * 1 = 4 kg

7 0
1 year ago
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