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ale4655 [162]
2 years ago
12

Rays QR and QS are tangents to circle P at R and S. If Q measures to 54°, find RS

Mathematics
1 answer:
Ainat [17]2 years ago
8 0

Answer: 126^{\circ}

Step-by-step explanation:

If we draw RP and PS, then in the quadrilateral formed, we know that \angle PRQ=\angle PSQ=90^{\circ}, and since angles in a quadrilateral add to 360 degrees, this means \angle SPR=126^{\circ}.

Thus, arc RS also measures 126 degrees

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Eva8 [605]
the answer is A, hope it helps
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3 years ago
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A definite integral of f(x)dx on the interval a to b probably SHOULDN'T be used:
OLga [1]
= cos( -x ) * [ - sin( - x ) ] = cosx * sinx ;
cosx * sin x is the right answer !
6 0
3 years ago
Diane must choose a number between 61 and 107 that is a multiple of 4,7, and 14 . Write all the numbers that she could choose.
Gwar [14]

Answer:

84

Step-by-step explanation:

only three number are a multiple of 14

14 * 5 = 70

14 * 6 = 84

14 * 7 = 98

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7 0
2 years ago
The graph of an inverse trigonometric function passes through the point (1, pi/2). Which of the following could be the equation
rodikova [14]

Answer: C) y=sin^-1 x

Step-by-step explanation:

Since, the graph of an inverse trigonometric function will pass through the point (1,\frac{\pi}{2}),

If this point satisfies the function,

For the function y=cos^{-1} x

If x = 1

y=cos^{-1}1=0

Thus,  (1,\frac{\pi}{2}) is not satisfying function  y=cos^{-1} x,

⇒ The graph of   y=cos^{-1} x is not passing through the point  (1,\frac{\pi}{2})

For the function y=cot^{-1}x

If x = 1

y=cot^{-1}1=\frac{\pi}{4}

Thus,  (1,\frac{\pi}{2}) is not satisfying function y=cot^{-1}x,

⇒ The graph of   y=cot^{-1}x is not passing through the point  (1,\frac{\pi}{2})

For the function y=sin^{-1} x

If x = 1

y=sin^{-1}1=\frac{\pi}{2}

Thus,  (1,\frac{\pi}{2}) is satisfying function y=sin^{-1} x,

⇒ The graph of   y=sin^{-1} x is passing through the point  (1,\frac{\pi}{2}).

For the function y=tan^{-1}x

If x = 1

y=tan^{-1}1=\frac{\pi}{4}

Thus,  (1,\frac{\pi}{2}) is not satisfying function  y=cos^{-1} x,

⇒ The graph of   y=tan^{-1} x is not passing through the point (1,\frac{\pi}{2}).

Hence, Option C is correct.

3 0
3 years ago
How much work in foot-pound is required to move a block 10 feet if the force is 200 lb
KatRina [158]

             Work = (force) x (distance)

                       = (200 lb) x (10 ft)  =  2,000 ft-lbs .

4 0
3 years ago
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