Hi Mackenzie.
Given that we have a probability question with the term "or", we are going to be adding individual probabilities.
We have Ethan, Hannah, and Sophie all included with the drawing.
This means we need to add each of their individual probabilities, 1/1200, together.
1/1200 + 1/1200 + 1/1200 = 3/1200;
To simplify: 1/400
Your answer is:
The probability of Ethan, Hannah, or Sophie being drawn is 1/400.
I hope this helps!
25 + 6 - 15 + 25 - 10 + 14 - 21
31 - 15 + 25 - 10 + 14 - 21
16 + 25 - 10 + 14 - 21
41 - 10 + 14 - 21
31 + 14 - 21
45 - 21
24
Vicki: 10 + 10 + 20 = 40
Johnny: 10 + 10 + 30 = 50
50 - 40 = 10 birds
Answer:
Step-by-step explanation:
We are told the school sold raffle tickets, and each ticket has a digit either 1, 2, or 3. The school also sold 2 tickets with the number 000.
Therefore we have the following raffle tickets:
123
132
213
231
312
321
000
000
From the given information, we can deduce that the school sold 8 tickets and only one ticket can contain the number arrangement of 123, but 000 appeared twice.
Probability of 123 to be picked=
1/8 => 0.125
Probability of 000 to be picked=
2/8 => 0.25
Since the probability of 000 to be picked is greater than 123, a ticket number of 000 is more likely to be picked
