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Ratling [72]
3 years ago
7

Have Retirement Benefits

Mathematics
1 answer:
charle [14.2K]3 years ago
5 0

Answer:

(a) The probability of the intersection of events "man" and "yes" is 0.55.

(b) The probability of the intersection of events "no" and "man" is 0.10.

(c) The probability of the union of events "woman" or "no" is 0.45.

Step-by-step explanation:

The information provided is:

             Yes    No   Total

Men       275   50     325

Women  150   25      175

Total      425   75      500

(a)

Compute the probability that a randomly selected employee is a man and a has retirement benefits as follows:

P(M\cap Y)=\frac{n(M\cap Y)}{N}=\frac{275}{500}=0.55

Thus, the probability of the intersection of events "man" and "yes" is 0.55.

(b)

Compute the probability that a randomly selected employee does not have retirement benefits and is a man as follows:

P(N\cap M)=\frac{n(N\cap M)}{N}=\frac{50}{500}=0.10

Thus, the probability of the intersection of events "no" and "man" is 0.10.

(c)

Compute the probability that a randomly selected employee is a woman or has no retirement benefits as follows:

P(W\cup N)=P(W)+P(N)-P(W\cap N)=\frac{175}{500}+\frac{75}{500}-\frac{25}{500}=0.45

Thus, the probability of the union of events "woman" or "no" is 0.45.

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The square root of a perfect square is not a whole number.
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solo el 20% de los empleados de la población civil que está en una base militar restringida porta su identificación personal. Si
prisoha [69]

Usando la distribución binomial, hay una probabilidad de 0.8926 = 89.26% de que el guardia de seguridad encuentre al menos uno en la base militar restringida.

<h3>¿Qué es la distribución binomial?</h3>

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

C_{n,x} = \frac{n!}{x!(n-x)!}

Los parámetros son:

  • n es el número de ensayos.
  • p es la probabilidad de éxito en un ensayo
  • x es el número de éxitos

En este problema, hay que:

  • 20% de los empleados de la población civil que está en una base militar restringida porta su identificación personal, o sea p = 0.2.
  • Llegan 10 empleados, o sea, n = 10.

La probabilidad de que el guardia de seguridad encuentre al menos uno en la base militar restringida es dada por:

P(X \geq 1) = 1 - P(X = 0)

En que:

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{10,0}.(0.2)^{0}.(0.8)^{10} = 0.1074

Por eso:

P(X \geq 1) = 1 - P(X = 0) = 1 - 0.1074 = 0.8926

Hay una probabilidad de 0.8926 = 89.26% de que el guardia de seguridad encuentre al menos uno en la base militar restringida.

Puede-se aprender más a cerca de la distribución binomial en brainly.com/question/25132113

3 0
2 years ago
Value of t? 1.4t — 0.4 (t — 3.1) = 5.8
IceJOKER [234]

Hi!

<h3>Use the distribution property</h3>

1.4t — 0.4 * t - 0.4 * —3.1 = 5.8

1.4t — 0.4t - 1.24 = 5.8

<h3>Simplify</h3>

1t - 1.24 = 5.8

<h3>Add 1.24 to both sides</h3>

1t - 1.24 + 1.24 = 5.8 + 1.24

1t = 7.04

<u>t = 7.04</u>

<h2>The answer is t = 7.04</h2>

Hope this helps! :)

-Peredhel

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A shop is selling notebooks for £1.50 each.
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Answer:

18 . 75

Step-by-step explanation:

1.50's half is 0.75 , Then multiply £1.50 × £25

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