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Travka [436]
2 years ago
13

6. What is an equation of the line that passes through the point (6,8)

Mathematics
1 answer:
Maru [420]2 years ago
6 0

Answer:

x = 6

Step-by-step explanation:

y = 3 is a horizontal line parallel to the x- axis and passing through all points with a y- coordinate of 3

A line perpendicular to this will be a vertical line parallel to the y- axis with equation

x = c ( c is the value of the x- coordinates the line passes through )

the line passes through (6, 8 ) with x- coordinate 6 , then

x = 6 ← equation of perpendicular line

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3 years ago
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Si a los lados de un cuadrado se le aumenta en 3 y 5 m respectivamente la superficie del nuevo rectangulo es 440m .Encontrar el
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Answer:

El lado del cuadrado inicial es 17 m.

Step-by-step explanation:

El área de un rectángulo se calcula a partir de los dos lados diferentes. Siendo a y b el valor de ambos lados, el área de la figura es el producto de los dos lados contiguos del rectángulo.

A los lados de un cuadrado se le aumenta en 3 y 5 m respectivamente la superficie del nuevo rectángulo es 440 m². Siendo x el lado del cuadrado inicial, entonces el área del rectángulo se puede expresar como:

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Resolviendo:

x*x + 5*x + 3*X + 3*5= 440

x² + 8*x + 15=440

x² + 8*x + 15 -440= 0

x² + 8*x -425= 0

Una función cuadrática de la forma a*x² + b*x + c= 0 se puede resolver mediante la expresión:

\frac{-b+-\sqrt{b^{2}-4*a*c } }{2*a}

En este caso, a=1, b=8 y c=425. Reemplazando:

\frac{-8+-\sqrt{8^{2}-4*1*(-425) } }{2*1}

Resolviendo:

\frac{-8+\sqrt{8^{2}-4*1*(-425) } }{2*1}= \frac{-8+\sqrt{64+1700} }{2*1}= \frac{-8+\sqrt{1764 } }{2}= \frac{-8+42 }{2}= \frac{34}{2} = 17

y

\frac{-8-\sqrt{8^{2}-4*1*(-425) } }{2*1}= \frac{-8-\sqrt{64+1700} }{2*1}= \frac{-8-\sqrt{1764 } }{2}= \frac{-8-42 }{2}= \frac{-50}{2} = -25

Como las longitudes no pueden ser negativas, <u><em>el lado del cuadrado inicial es 17 m.</em></u>

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