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Angelina_Jolie [31]
3 years ago
13

Complete the point-slope equation of the line through (3,6)(3,6)left parenthesis, 3, comma, 6, right parenthesis and (5,-8)(5,−8

)left parenthesis, 5, comma, minus, 8, right parenthesis.
Mathematics
1 answer:
ArbitrLikvidat [17]3 years ago
5 0

Answer:

The required equation of line in point-slope form is:

y-6 = -7(x-3)

Step-by-step explanation:

Given points are:

(x1,y1) = (3,6)

(x2,y2) = (5,-8)

The point-slope form of an equation is given by:

y-y_1 = m(x-x_1)

Here m is slope of the line and (x1,y1) is a point on line

The slope is calculated using the formula:

m = \frac{y_2-y_1}{x_2-x_1}

Putting the values we get

m = \frac{-8-6}{5-3}\\m=\frac{-14}{2}\\m= -7

Putting in the equation

y-y_1 = -7(x-x_1)

Now we have to put a point in the equation, putting (3,6) in the equation

y-6 = -7(x-3)

Hence,

The required equation of line in point-slope form is:

y-6 = -7(x-3)

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Step-by-step explanation:


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Which statements about the line that passes through (−2, 0) and (2, −4) are true? Select all that apply.
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Your question is incomplete.

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But if this is your question in the picture below then this is your answer..

Answer:

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Step-by-step explanation:  

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Zigmanuir [339]

Answer:

Ai. Arithmetic sequence

Aii. Tn = 5 + 7n

Bi. Geometric

Bii. Tn = 8 × 2ⁿ¯¹

Step-by-step explanation:

To successfully answer the questions given above, note the following:

1. If the sequence is Arithmetic, then:

2nd – 1st = 3rd – 2nd = common difference (d)

2. If the sequence is geometric, then,

2nd / 1st = 3rd / 2nd = common ratio (r)

3. A sequence can not be arithmetic geometric at the same time.

4. The nth term of arithmetic sequence is:

Tn = a + (n – 1)d

5. The nth term of geometric sequence is:

Tn = arⁿ¯¹

A. Sequence => 12, 19, 26

i. Determination of the type of sequence.

We'll begin by calculating the common difference

1st term = 12

2nd term = 19

3rd term = 26

Common difference (d) = 2nd – 1st

d = 19 – 12 = 7

OR

d = 3rd – 2nd

d = 26 – 19 = 7

Since a common difference exist in the sequence, the sequence is arithmetic sequence.

ii. Determination of the nth term.

Common difference (d) = 7

1st term (a) = 12

nth term (Tn) =?

Tn = a + (n – 1)d

Tn = 12 + (n – 1)7

Tn = 12 + 7n – 7

Tn = 5 + 7n

B. Sequence => 8, 16, 32

Bi. Determination of the type of sequence.

Let us begin by calculating the common ratio.

1st term = 8

2nd term = 16

3rd term = 32

Common ratio (r) = 2nd / 1st

r = 16 / 8

r = 2

OR

r = 3rd / 2nd

r = 32 / 16

r = 2

Since a common ratio exist in the sequence, the sequence is geometric.

Bii. Determination of the nth term.

Common ratio(r) = 2

1st term (a) = 8

nth term =?

Tn = arⁿ¯¹

Tn = 8 × 2ⁿ¯¹

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