Question

???? please help lol

Answer 1

Answer:

1. 150π ft²
2. 10π ft.

Step-by-step explanation:

Area of the sector :

$Area (sector) = \pi r^{2} \times \frac{\theta}{360^{o}}$

Finding the area given r = 30 ft. and θ = 60° :

⇒ Area = π × (30)² × 60/360

⇒ Area = π × 900/6

⇒ Area = 150π ft²

===========================================================

Length of the arc :

$Length (arc) =2 \pi r} \times \frac{\theta}{360^{o}}$

Finding the arc length given r = 30 ft. and θ = 60° :

⇒ Arc Length = 2 × π × 30 × 60/360

⇒ Arc Length = 60/6 × π

⇒ Arc Length = 10π ft.

Answer 2

Answer:

1. 150π ft²

2. 10π ft²

Step-by-step explanation:

Hello there!

Here is how we solve the given problem:

1. Area of the sector of a circle refers to the fractional circle area. Which is given by; (∆°/360°) × πr². Where ∆° is the angle subtended by the arc.
2. the arc length also refers to the length swept by the arc with angle theta (∆°) - subtended. Given by

L = ∆°/360° ×2πr

From our problem,

∆ = 60°, r = 30ft

Lets substitute the values

1. A = (∆°/360°) × πr²

= 60°/360° × π × 30²

= 150π ft²

2. L = ∆°/360° × 2πr

= (60/360) × 2 × 30 × π

= 10π ft²

NOTE:

Use the formulas given below to be on a save side;

1. A = (∆°/360°) × πr²
2. L = ∆°/360° × 2πr.

I hope this helps.

Have a nice studies. :)