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2 years ago

5 feet to 31 inches write the ratio of the first measurement to the second measurement compare in inches

Mathematics

1 answer:

castortr0y [4]2 years ago

3 0

Answer:

60:31

Step-by-step explanation:

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Each side of a square classroom is 8 yards long. The school wants to replace the carpet in the classroom with the new carpet tha

shusha [124]

Answer: $2624

Step-by-step explanation:

Well since it’s square yards that means find the area first and since it’s a square and your given 1 side then it’s 8(8)=64. So there’s 64 square yards and since it’s $41 per square yard then multiply 64(41) which will give you $2624

7 0

3 years ago

The critical value t* gets larger as the confidence level increases. True or false?

posledela

Answer:

We can find the critical value $t_{\alpha/2}$

And for this case if the confidence increase the critical value increase so then this statement is True

Step-by-step explanation:

For a confidence level given c, we can find the significance level like this:

$\alpha=1 -c$

And with the degrees of freedom given by:

$df=n-1$

We can find the critical value $t_{\alpha/2}$

And for this case if the confidence increase the critical value increase so then this statement is True

5 0

3 years ago

What are the x-coordinates for the maximum points in the function f(x)=4cos(2x-pi) from x=0 to x=2pi?

wel

The maximum value attained by the function will be 4
4 = 4cos(2x - π)
cos(2x - π) = 1
2x - π = 0
x = (nπ)/2
From x = 0 to x = 2π, n = 1, 2, etc
The equation will yield +4 for odd values of n and -4 for even values of n

6 0

3 years ago

A shopper is standing on level ground 800 feet from the base of a 250 foot tall department store the shopper looks up and sees a

Aleks04 [339]

Answer:

The elevation to the top of the building from the point on the ground where the shopper is standing is = 17.35°

Step-by-step explanation:

From the ΔABC

AB = height of the building = 250 feet

BC = 800 ft

Angle of elevation = $\theta$

$\tan \theta = \frac{AB}{BC}$

$\tan \theta = \frac{250}{800}$

$\tan \theta$ = 0.3125

$\theta = 17.35$ °

Therefore the elevation to the top of the building from the point on the ground where the shopper is standing is = 17.35°

8 0

3 years ago

H(x)=1/8x^3-x^2<br><br> Over which interval does h have a positive average rate of change?

lara31 [8.8K]

Answer:

$(-\infty,0)\cup(\frac{16}{3},\infty)\\That \ is x\frac{16}{3}$

Step-by-step explanation:

$h(x)=\frac{1}{8}x^{3} -x^{2} \\\\Differentiate \ h(x) \ with \ respect \ to \ x\\h'(x)=\frac{3}{8}x^{2} -2x$

For positive rate of change $h'(x)>0$

$\frac{3}{8} x^{2} -2x>0\\x(\frac{3}{8}x-2)>0\\\\ When \ x0 \ (multiplication \ of \ two \ positives \ is \ positive)\\\\h'(x)>0 \ when \ x\frac{16}{3} \\\\$

6 0

4 years ago