What are the x-coordinates for the maximum points in the function f(x)=4cos(2x-pi) from x=0 to x=2pi?
1 answer:
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Answer:
<h2> y = 6x - 1</h2>Step-by-step explanation:
(0, -1) ⇒ x₁ = 0, y₁ = -1
(1, 5) ⇒ x₂ = 1, y₂ = 5
So the slope:
The slope-intercept form of the equation of line is y = mx + b, where m is the slope and b is the y-intercept of the line.
(0, -1) ⇒ x₀ = 0, y₀ = -1 ⇒ b = -1
Therefore:
y = 6x - 1 ← the slope-intercept form of the equation