The quadratic formula is above.
You want each equation in standard form: ax^2 + bx + c = 0
I begin each problem by defining variables.
For instance 3. Is in standard form. X^2 -2x - 3 = 0. a = 1, b = -2, c = -3
Now use quadratic formula: x = [- b + or - sqrt(b^2 - 4ac)]\2a
First find average
(5+5+5+5+7+9)/6=6
now see how much they each are differnt
5 to 6 is 1
5 to 6 is 1
5 to 6 is 1
5 to 6 is 1
7 to 6 is 1
9 to 6 is 3
average those
(1+1+1+1+1+3)/6=8/6=4/3=1.333
answer is 1.33
Answer:
135
Step-by-step explanation:
15 x 9 = 135
Answer:
No solution
Step-by-step explanation:
Note how "2x" shows up in both equations. This suggests doing a substitution to solve the system.
Focus first on the first equation. Solving 2x - y = 7 for 2x, we get:
2x = y + 7.
Next, we substitute y + 7 for 2x in the second equation:
y = (y + 7) + 3.
Simplifying this produces:
0 = 10
This is not true and can never be true. Thus, this system has no solution.