We should confirm that f(x) has an inverse in the first place. If it does, then
![f\left(f^{-1}(x)\right) = x](https://tex.z-dn.net/?f=f%5Cleft%28f%5E%7B-1%7D%28x%29%5Cright%29%20%3D%20x)
Given that f(x) = x/(2 - x), we have
![f\left(f^{-1}(x)\right) = \dfrac{f^{-1}(x)}{2 - f^{-1}(x)} = x](https://tex.z-dn.net/?f=f%5Cleft%28f%5E%7B-1%7D%28x%29%5Cright%29%20%3D%20%5Cdfrac%7Bf%5E%7B-1%7D%28x%29%7D%7B2%20-%20f%5E%7B-1%7D%28x%29%7D%20%3D%20x)
Solve for the inverse:
![\dfrac{f^{-1}(x)}{2 - f^{-1}(x)} = x](https://tex.z-dn.net/?f=%5Cdfrac%7Bf%5E%7B-1%7D%28x%29%7D%7B2%20-%20f%5E%7B-1%7D%28x%29%7D%20%3D%20x)
![f^{-1}(x) = 2x - x f^{-1}(x)](https://tex.z-dn.net/?f=f%5E%7B-1%7D%28x%29%20%3D%202x%20-%20x%20f%5E%7B-1%7D%28x%29)
![f^{-1}(x) + x f^{-1}(x) = 2x](https://tex.z-dn.net/?f=f%5E%7B-1%7D%28x%29%20%2B%20x%20f%5E%7B-1%7D%28x%29%20%3D%202x)
![f^{-1}(x) (1 + x) = 2x](https://tex.z-dn.net/?f=f%5E%7B-1%7D%28x%29%20%281%20%2B%20x%29%20%3D%202x)
![f^{-1}(x) = \dfrac{2x}{1+x}](https://tex.z-dn.net/?f=f%5E%7B-1%7D%28x%29%20%3D%20%5Cdfrac%7B2x%7D%7B1%2Bx%7D)
Then
![f^{-1}(-2) = \dfrac{2(-2)}{1-2} = \boxed{4}](https://tex.z-dn.net/?f=f%5E%7B-1%7D%28-2%29%20%3D%20%5Cdfrac%7B2%28-2%29%7D%7B1-2%7D%20%3D%20%5Cboxed%7B4%7D)
Note that this is the same as solve for x when f(x) = -2 :
x/(2 - x) = -2 ⇒ x = 4
Although you have not presented any choices for this question, I will proceed on discussing what the possible answer might be depending on the description you gave. The answer to this mathematical question would be vertical angles. This is because vertical angles are always equal to each other.
Answer:
75*25%+(38+40)*50%+85*25%=59.5
Step-by-step explanation:
E: None of the above
the angle is adj. and no letters are adj. to ABC
Multiple the top equation by 2 and rearrange so that -7 is equal to the others.
-10x+2y=-14
-3x-2y=-12
——————-
-13x=-26
Divide both by -13
x=2