Answer: See Below
Step-by-step explanation:
Line equation is y = ax +b. We need to solve for a and b
First we will solve for the slope (a)
Given that it is perpendicular to 2x - 6y = 12, we know that our slope a is the negative reciprocal of the slope of this line. Lets put this line in point-slope format.
2x - 6y = 12
-6y = -2x + 12
y = (1/3)x - 2
This line has a slope of 1/3 so our slope is the negative reciprocal of that. Our slope is -3
We can plug that slope into our line equation in place of a
y = -3x + b
Now we can plug in (3,6) to solve for b
y = -3x + b
6 = -3(3) + b
6 = -9 + b
15 = b
Therefore our line equation is:
y = -3x + 15
