Question

write the equation of the line that passes through the point and is perpendicular to the given line (3,6) ; 2x- 6y = 12

Answer 1

Answer: See Below

Step-by-step explanation:

Line equation is y = ax +b. We need to solve for a and b

First we will solve for the slope (a)

Given that it is perpendicular to 2x - 6y = 12, we know that our slope a is the negative reciprocal of the slope of this line. Lets put this line in point-slope format.

2x - 6y = 12

-6y = -2x + 12

y = (1/3)x - 2

This line has a slope of 1/3 so our slope is the negative reciprocal of that. Our slope is -3

We can plug that slope into our line equation in place of a

y = -3x + b

Now we can plug in (3,6) to solve for b

y = -3x + b

6 = -3(3) + b

6 = -9 + b

15 = b

Therefore our line equation is:

y = -3x + 15