Answer:
use logarithms
Step-by-step explanation:
Taking the logarithm of an expression with a variable in the exponent makes the exponent become a coefficient of the logarithm of the base.
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You will note that this approach works well enough for ...
a^(x+3) = b^(x-6) . . . . . . . . . . . variables in the exponents
(x+3)log(a) = (x-6)log(b) . . . . . a linear equation after taking logs
but doesn't do anything to help you solve ...
x +3 = b^(x -6)
There is no algebraic way to solve equations that are a mix of polynomial and exponential functions.
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Some functions have been defined to help in certain situations. For example, the "product log" function (or its inverse) can be used to solve a certain class of equations with variables in the exponent. However, these functions and their use are not normally studied in algebra courses.
In any event, I find a graphing calculator to be an extremely useful tool for solving exponential equations.
Answer:
2880
Step-by-step explanation:
The total number of people affected by flu during the 2nd and 3rd week of January, 1200 + 1680 = 2880
She needs to cover 17&1/4 ft^2
Explanation:
You need to multiply the lxW in order to get the area.
Step-by-step explanation:
The volume of the cube below is 250.047 m^3. The side length could be between which sets of numbers below?
A. 4 cm and 5cm
B 5cm and 6 cm
C. 6 cm and 7 cm
D. 7 cm and 8 cm
ans.C
