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2 years ago

For the following exercises, determine whether the functions are even, odd, or neither.

Mathematics

1 answer:

stealth61 [152]2 years ago

6 0

Answer:

The solutions of the equation |2 x-3|=17

are x=10

and x=-7

Step-by-step explanation:

Given equations is |2 x-3|=17.

It is required to find out the values of x satisfying the given equation.

To find it out, use the fact that the solution of this type of equation is 2x-3=17.

Or 2x-3=-17 and simplify the equations using simple mathematical operations.

Step 1 of 2

Solve the equation 2x-3=17,

Add 3 on both sides of the equation 2x-3=17,

2x-3+3=17+3

2x=20

Divide by 2 on both sides of the equation 2x=20,

$\begin{aligned}&\frac{2 x}{2}=\frac{20}{2} \\&x=10\end{aligned}$

Step 2 of 2

Solve the equation 2x-3=-17,

Add 3 on both sides of the equation 2x-3=-17,

$2 x-3+3=-17+3$\\ $2 x=-14$

Divide by 2 on both sides of the equation 2x=-14,

$\begin{aligned}&\frac{2 x}{2}=\frac{-14}{2} \\&x=-7\end{aligned}$

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Which numbers below are odd? Check all that apply.

andrew-mc [135]

Answer:
C and B I think

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3 years ago

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Solve for . Simplify your answer as much as possible. please help

Sonja [21]

Answer:

$x=-6$

Step-by-step explanation:

So we have the equation:

$-34=7(x+8)+8x$

First, distribute the 7 into the (x+8) and simplify:

$-34=7(x)+7(8)+8x\\-34=7x+56+8x$

Combine the like terms 7x and 8x by adding them together:

$-34=56+15x$

Subtract 56 from both sides to isolate the x:

$-34-56=15x+56-56\\15x=-90$

Divide both sides by 15 to get x:

$x=-90/15=-6$

5 0

3 years ago

What function represents the pattern shown in the table?

Pavlova-9 [17]

Given:

The table of values of an exponential function.

To find:

The function for the given table of values.

Solution:

The general exponential function is:

$y=ab^x$ ...(i)

Where, a is the initial value and b is growth factor.

From the given table it is clear that the function passes through the points (1,9) and (2,36). It means the function must be true for these two points.

$9=ab^1$ ...(ii)

$36=ab^2$ ...(iii)

On dividing (iii) by (ii), we get

$\dfrac{36}{9}=\dfrac{ab^2}{ab}$

$4=b$

Putting $b=4$ in (ii), we get

$9=a(4)^1$

$\dfrac{9}{4}=a$

Putting $a=\dfrac{9}{4},b=4$ in (i), we get

$y=\dfrac{9}{4}(4)^x$

$y=9(4)^{x-1}$

The function notation with variable n is:

$f(n)=9(4)^{n-1}$

Therefore, the correct option is D.

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3 years ago

2/3 - (30 divided by 5) + 9=

irakobra [83]

2^3 - (30 / 5) + 9

8 - (6) + 9

2 + 9

11 is your answer

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3 years ago

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Write an equation of the parabola that opens up whose vertex (−1, 2) is 3 units from the focus. (Vertex form or Parabola Form is

TEA [102]

Answer:

y2 = 4ax (opens right, a > 0)

y2 = -4ax (opens right, a > 0)

x2 = 4ay (opens up, a > 0)

x2 = -4ay (opens down, a > 0)

Vertex at (h, k) :

(y - k)2 = 4a(x - h) (opens right, a > 0)

(y - k)2 = -4a(x - h) (opens right, a > 0)

(x - h)2 = 4a(y - k) (opens up, a > 0)

(x - h)2 = -4a(y - k) (opens down, a > 0)

Equation of a Parabola in Vertex form

Vertex at Origin :

y = ax2 (opens up, a > 0)

y = -ax2 (opens down, a > 0)

x = ay2 (opens right, a > 0)

x = -ay2 (opens left, a > 0)

Vertex at (h, k) :

y = a(x - h)2 + k (opens up, a > 0)

y = -a(x - h)2 + k (opens down, a > 0)

x = a(y - k)2 + h (opens right, a > 0)

y = -a(y - k)2 + h (opens left, a > 0)

Step-by-step explanation:

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3 years ago