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lbvjy [14]
2 years ago
11

For the following exercises, determine whether the functions are even, odd, or neither.

Mathematics
1 answer:
stealth61 [152]2 years ago
6 0

Answer:

The solutions of the equation |2 x-3|=17

are x=10

and x=-7

Step-by-step explanation:

Given equations is |2 x-3|=17.

It is required to find out the values of x satisfying the given equation.

To find it out, use the fact that the solution of this type of equation is 2x-3=17.

Or 2x-3=-17 and simplify the equations using simple mathematical operations.

Step 1 of 2

Solve the equation 2x-3=17,

Add 3 on both sides of the equation 2x-3=17,

2x-3+3=17+3

2x=20

Divide by 2 on both sides of the equation 2x=20,

$$\begin{aligned}&\frac{2 x}{2}=\frac{20}{2} \\&x=10\end{aligned}$$

Step 2 of 2

Solve the equation 2x-3=-17,

Add 3 on both sides of the equation 2x-3=-17,

$2 x-3+3=-17+3$\\ $2 x=-14$

Divide by 2 on both sides of the equation 2x=-14,

$$\begin{aligned}&\frac{2 x}{2}=\frac{-14}{2} \\&x=-7\end{aligned}$$

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Step-by-step explanation:

7 0
4 years ago
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The solution of [5x(4+6)-9]
Anna35 [415]

Answer:

41

Step-by-step explanation:

BIDMAS

[5 x (4 + 6) - 9]

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3 0
3 years ago
Find the equation of a parabola with a vertical axis and its vertex at the origin and passing through the point (-2, 3).
jonny [76]

Answer:

y=\frac{3}{4}x^2

Step-by-step explanation:

Hi there!

Because we're given the vertex of the parabola, we can determine its equation in vertex form:

y=a(x-h)^2+k where the vertex is (h,k)

Plug in the vertex (0,0)

y=a(x-0)^2+0\\y=a(x)^2\\y=a(x-0)^2+0\\y=ax^2

Now, we must solve for a. Plug in the given point (-2,3) and solve for a:

3=a(-2)^2\\3=4a\\\frac{3}{4} =a

Therefore, the value of a is \frac{3}{4}. Plug this back into y=ax^2:

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I hope this helps!

5 0
3 years ago
A customer buys five cans of baked beans, four packets of brown sugar and two packets of biscuits from a supermarket.He gives th
Naily [24]
Can of baked beans = x 
packet of brown sugar = y
packet of biscuit = z

5x + 4y + 2z = 150 - 26 ⇒ 5x + 4y + 2z = 124 is the total cost of all items.

can of baked beans = x = 1/2 of z
packet of sugar = y = z - 3

5(z/2) + 4(z-3) + 2z = 124
5z/2 + 4z - 12 + 2z = 124
5z/2 + 6z = 124 + 12
2(5z/2 + 6z) = 2(136)
5z + 12z = 272
17z = 272
z = 16 cost of a packet of biscuit.

x = 1/2 of z = 16/2 = 8 cost of a can of baked beans
y = z - 3 = 16 - 3 = 13 cost of a packet of sugar

5x + 4y + 2z = 124
5(8) + 4(13) + 2(16) = 124
40 + 52 + 32 = 124
124 = 124

8(8) + 1(13) + 6(16) = 64 + 13 + 96 = 173 total cost on question 3.
7 0
4 years ago
Explain how to write 2.14 x 10 to the negative power of 5 in standard form by moving the decimal point
Hatshy [7]

Answer:

21.4 * 10^(-5)

Step-by-step explanation:

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