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lbvjy [14]
2 years ago
11

For the following exercises, determine whether the functions are even, odd, or neither.

Mathematics
1 answer:
stealth61 [152]2 years ago
6 0

Answer:

The solutions of the equation |2 x-3|=17

are x=10

and x=-7

Step-by-step explanation:

Given equations is |2 x-3|=17.

It is required to find out the values of x satisfying the given equation.

To find it out, use the fact that the solution of this type of equation is 2x-3=17.

Or 2x-3=-17 and simplify the equations using simple mathematical operations.

Step 1 of 2

Solve the equation 2x-3=17,

Add 3 on both sides of the equation 2x-3=17,

2x-3+3=17+3

2x=20

Divide by 2 on both sides of the equation 2x=20,

$$\begin{aligned}&\frac{2 x}{2}=\frac{20}{2} \\&x=10\end{aligned}$$

Step 2 of 2

Solve the equation 2x-3=-17,

Add 3 on both sides of the equation 2x-3=-17,

$2 x-3+3=-17+3$\\ $2 x=-14$

Divide by 2 on both sides of the equation 2x=-14,

$$\begin{aligned}&\frac{2 x}{2}=\frac{-14}{2} \\&x=-7\end{aligned}$$

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Answer:
C and B I think
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Solve for . Simplify your answer as much as possible. please help
Sonja [21]

Answer:

x=-6

Step-by-step explanation:

So we have the equation:

-34=7(x+8)+8x

First, distribute the 7 into the (x+8) and simplify:

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Combine the like terms 7x and 8x by adding them together:

-34=56+15x

Subtract 56 from both sides to isolate the x:

-34-56=15x+56-56\\15x=-90

Divide both sides by 15 to get x:

x=-90/15=-6

5 0
3 years ago
What function represents the pattern shown in the table?
Pavlova-9 [17]

Given:

The table of values of an exponential function.

To find:

The function for the given table of values.

Solution:

The general exponential function is:

y=ab^x        ...(i)

Where, a is the initial value and b is growth factor.

From the given table it is clear that the function passes through the points (1,9) and (2,36). It means the function must be true for these two points.

9=ab^1        ...(ii)

36=ab^2       ...(iii)

On dividing (iii) by (ii), we get

\dfrac{36}{9}=\dfrac{ab^2}{ab}  

4=b  

Putting b=4 in (ii), we get

9=a(4)^1

\dfrac{9}{4}=a

Putting a=\dfrac{9}{4},b=4 in (i), we get

y=\dfrac{9}{4}(4)^x

y=9(4)^{x-1}

The function notation with variable n is:

f(n)=9(4)^{n-1}

Therefore, the correct option is D.

7 0
3 years ago
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Write an equation of the parabola that opens up whose vertex (−1, 2) is 3 units from the focus. (Vertex form or Parabola Form is
TEA [102]

Answer:

y2  =  4ax (opens right, a > 0)

y2  =  -4ax (opens right, a > 0)

x2  =  4ay (opens up, a > 0)

x2  =  -4ay (opens down, a > 0)

Vertex at (h, k) :  

(y - k)2  =  4a(x - h) (opens right, a > 0)

(y - k)2  =  -4a(x - h) (opens right, a > 0)

(x - h)2  =  4a(y - k) (opens up, a > 0)

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Equation of a Parabola in Vertex form

Vertex at Origin :  

y  =  ax2 (opens up, a > 0)

y  =  -ax2 (opens down, a > 0)

x  =  ay2 (opens right, a > 0)

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Vertex at (h, k) :  

y  =  a(x - h)2 + k (opens up, a > 0)

y  =  -a(x - h)2 + k (opens down, a > 0)

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y  =  -a(y - k)2 + h (opens left, a > 0)

Step-by-step explanation:

7 0
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