Archimedes is the father of mathematics.
Step-by-step explanation:
To find the radius of the sphere we must convert the inches to centimeters
Using the conversation
1 inch = 2.54 cm
If 1 inch = 2.54 cm
4.17 inch = 2.54 × 4.17 = 10.59 cm
<h2>a).</h2>
We can find the radius using the formula

From the question
diameter = 10.59 cm
So we have

<h3>radius = 5.30 cm</h3>
<h2>b).</h2>
Surface area of a sphere= 4πr²
where
r is the radius
Surface area = 4(5.30)²π
= 112.36π
= 352.989
We have the answer as
<h3>Surface area = 353 cm²</h3>
<h2>c).</h2>
Volume of a sphere is given by

r = 5.30
The volume of the sphere is

= 623.61451
We have the answer as
<h2>Volume = 623.6 cm³</h2>
Hope this helps you
Answer:
43,45
Step-by-step explanation:
43+45=88
I have attached a screenshot with the images of the two popcorn bags used by the theater.
Part (a):Bag A:Volume of bag = area of base * height
Volume of bag = length * width * height
We have:
volume = 96 in³
length = 3 in
width = 4 in
Therefore:
96 = 3 * 4 * height
96 = 12 * height
height of bag A = 8 inBag B:Volume of bag = area of base * height
Volume of bag = length * width * height
We have:
volume = 96 in³
length = 4 in
width = 4 in
Therefore:
96 = 4 * 4 * height
96 = 16 * height
height of bag B = 6 inPart (b):To determine the amount of paper needed, we will need to calculate the surface of each bag. Excluding the top base, each bag will have 5 faces. Four side faces (each two opposite are equal) and the base.
Bag A:Surface area = area of base + 2*area of front face + 2*area of side face
Surface area = (3*4) + 2(8*4) + 2(8*3)
Surface area = 12 + 64 + 48
Surface area of bag A = 124 in²Bag B:Surface area = area of base + 2*area of front face + 2*area of side face
Surface area = (4*4) + 2(6*4) + 2(6*4)
Surface area = 16 + 48 + 48
Surface area of bag B = 112 in²From the above calculations, we can deduce that
the theater should choose bag B in order to reduce the amount of paper needed.
Hope this helps :)
This question is incomplete. There is no way to get a volume from a single
length