Find the coordinate plane that represents the solution of this system y > -x

Complete the statement. Round to the nearest hundredth if necessary. 6 lb = *blank* oz

skad [1K]

Answer:

3 oz

Step-by-step explanation:

You have to divide 6 by 2 and you'll get the answer.

3 0

3 years ago

Please help. 50 points + brainliest

Korvikt [17]

Answer:

1. (a-c) $\sqrt{x}$ + b $\sqrt{y}$

2. 9m + 2 $\sqrt{n}$

3. 6a

4. (5a - 3b) $\sqrt{5y}$

Step-by-step explanation:

1. since a and c share the same squareroot x, you can combine these together.

2. First add like terms together. 4m - m + 6m = 9m. Then 5 $\sqrt{n}$ and -3 $\sqrt{n}$ combined equals 2 $\sqrt{n}$

3. First simplify the square roots. squareroot of 16 is 4. square root of 49 is 7. square root of 81 is 9. They are all multiplied by a in the expression. Thus 4a - 7a + 9a = 6a

4. First simplify the radicals, they are not perfect. square root of 125 is equivalent to sqrt(25 * 5), which sqrt of 25 is 5, but we keep the sqrt of 5. For sqrt of 45, it is the same as sqrt9 * sqrt5. sqrt of 9 is the same as 3 and we keep sqrt 5. Thus we get the below:

5a $\sqrt{5y}$ - 3b $\sqrt{5y}$

We can combine the two like terms and get the final answer above.

please give thanks by clicking the heart :)

3 0

3 years ago

Find the inverse of the function y= (x-4)3

Alinara [238K]

Answer:

Sowwy :< I don't know

Step-by-step explanation:

4 0

3 years ago

Joe earns $14 an hour and Blaine earns $18 per hour. Joe receives a raise of $1.75 every six months, and Blaine receives a raise

Katarina [22]

After 4 interval of six months, Joe to earn same hourly rate as Blaine

Solution:

Given that,

Amount earned by Joe = $ 14 per hour

Amount earned by Blaine = $ 18 per hour

Lets assume the number of six month intervals be "x"

Joe receives a raise of $1.75 every six months

Therefore,

Joe earning: 14 + 1.75(number of six month intervals)

Equation for Joe earning: 14 + 1.75x ------- eqn 1

Blaine receives a raise of $0.75 every six months

Therefore,

Blaine earning: 18 + 0.75(number of six month intervals)

Equation for Blaine earning: 18 + 0.75x ------------ eqn 2

The number of six-month intervals it will take Joe to earn the same hourly rate as Blaine,

Eqn 1 must be equal to eqn 2

$14+1.75x = 18+0.75x\\\\1.75x-0.75x = 18-14\\\\1x = 4\\\\x = 4$

Thus after 4 interval of six months, Joe to earn same hourly rate as Blaine.

8 0

3 years ago

One stats class consists of 52 women and 28 men. Assume the average exam score on Exam 1 was 74 (σ = 10.43; assume the whole cla

Svetllana [295]

Answer:

(A) What is the z- score of the sample mean?

The z- score of the sample mean is 0.0959

(B) Is this sample significantly different from the population?

No; at 0.05 alpha level (95% confidence) and (n-1 =79) degrees of freedom, the sample mean is NOT significantly different from the population mean.

Step -by- step explanation:

(A) To find the z- score of the sample mean,

X = 75 which is the raw score

¶ = 74 which is the population mean

S. D. = 10.43 which is the population standard deviation of/from the mean

Z = [X-¶] ÷ S. D.

Z = [75-74] ÷ 10.43 = 0.0959

Hence, the sample raw score of 75 is only 0.0959 standard deviations from the population mean. [This is close to the population mean value].

(B) To test for whether this sample is significantly different from the population, use the One Sample T- test. This parametric test compares the sample mean to the given population mean.

The estimated standard error of the mean is s/√n

S. E. = 16/√80 = 16/8.94 = 1.789

The Absolute (Calculated) t value is now: [75-74] ÷ 1.789 = 1 ÷ 1.789 = 0.559

Setting up the hypotheses,

Null hypothesis: Sample is not significantly different from population

Alternative hypothesis: Sample is significantly different from population

Having gotten T- cal, T- tab is found thus:

The Critical (Table) t value is found using

- a specific alpha or confidence level

- (n - 1) degrees of freedom; where n is the total number of observations or items in the population

- the standard t- distribution table

Alpha level = 0.05

1 - (0.05 ÷ 2) = 0.975

Checking the column of 0.975 on the t table and tracing it down to the row with 79 degrees of freedom;

The critical t value is 1.990

Since T- cal < T- tab (0.559 < 1.990), refute the alternative hypothesis and accept the null hypothesis.

Hence, with 95% confidence, it is derived that the sample is not significantly different from the population.

6 0

4 years ago

Find the coordinate plane that represents the solution of this system y > -x - 1 y + 4 ≤ x