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3 years ago

Please help. 50 points + brainliest

Mathematics

1 answer:

Korvikt [17]3 years ago

3 0

Answer:

1. (a-c) $\sqrt{x}$ + b $\sqrt{y}$

2. 9m + 2 $\sqrt{n}$

3. 6a

4. (5a - 3b) $\sqrt{5y}$

Step-by-step explanation:

1. since a and c share the same squareroot x, you can combine these together.

2. First add like terms together. 4m - m + 6m = 9m. Then 5 $\sqrt{n}$ and -3 $\sqrt{n}$ combined equals 2 $\sqrt{n}$

3. First simplify the square roots. squareroot of 16 is 4. square root of 49 is 7. square root of 81 is 9. They are all multiplied by a in the expression. Thus 4a - 7a + 9a = 6a

4. First simplify the radicals, they are not perfect. square root of 125 is equivalent to sqrt(25 * 5), which sqrt of 25 is 5, but we keep the sqrt of 5. For sqrt of 45, it is the same as sqrt9 * sqrt5. sqrt of 9 is the same as 3 and we keep sqrt 5. Thus we get the below:

5a $\sqrt{5y}$ - 3b $\sqrt{5y}$

We can combine the two like terms and get the final answer above.

please give thanks by clicking the heart :)

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Find T5(x) : Taylor polynomial of degree 5 of the function f(x)=cos(x) at a=0 . (You need to enter function.) T5(x)= Find all va

Burka [1]

Answer:

$\bf cos(x)\approx1-\displaystyle\frac{x^2}{2}+\displaystyle\frac{x^4}{4!}=\\\\=1-\displaystyle\frac{x^2}{2}+\displaystyle\frac{x^4}{24}$

The polynomial is an approximation with an error less than or equals to 0.002652 for x in the interval

[-1.113826815, 1.113826815]

Step-by-step explanation:

According to Taylor's theorem

$\bf f(x)=f(0)+f'(0)x+f''(0)\displaystyle\frac{x^2}{2}+f^{(3)}(0)\displaystyle\frac{x^3}{3!}+f^{(4)}(0)\displaystyle\frac{x^4}{4!}+f^{(5)}(0)\displaystyle\frac{x^5}{5!}+R_6(x)$

with

$\bf R_6(x)=f^{(6)}(c)\displaystyle\frac{x^6}{6!}$

for some c in the interval (-x, x)

In the particular case f

f(x)=cos(x)

we have

$\bf f'(x)=-sin(x)\\f''(x)=-cos(x)\\f^{(3)}(x)=sin(x)\\f^{(4)}(x)=cos(x)\\f^{(5)}(x)=-sin(x)\\f^{(6)}(x)=-cos(x)$

therefore

$\bf f'(x)=-sin(0)=0\\f''(0)=-cos(0)=-1\\f^{(3)}(0)=sin(0)=0\\f^{(4)}(0)=cos(0)=1\\f^{(5)}(0)=-sin(0)=0$

and the polynomial approximation of T5(x) of cos(x) would be

$\bf cos(x)\approx1-\displaystyle\frac{x^2}{2}+\displaystyle\frac{x^4}{4!}=\\\\=1-\displaystyle\frac{x^2}{2}+\displaystyle\frac{x^4}{24}$

In order to find all the values of x for which this approximation is within 0.002652 of the right answer, we notice that

$\bf R_6(x)=-cos(c)\displaystyle\frac{x^6}{6!}$

for some c in (-x,x). So

$\bf |R_6(x)|\leq|\displaystyle\frac{x^6}{6!}|=\displaystyle\frac{|x|^6}{6!}$

and we must find the values of x for which

$\bf \displaystyle\frac{|x|^6}{6!}\leq0.002652$

Working this inequality out, we find

$\bf \displaystyle\frac{|x|^6}{6!}\leq0.002652\Rightarrow |x|^6\leq1.90944\Rightarrow\\\\\Rightarrow |x|\leq\sqrt[6]{1.90944}\Rightarrow |x|\leq1.113826815$

Therefore the polynomial is an approximation with an error less than or equals to 0.002652 for x in the interval

[-1.113826815, 1.113826815]

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3 years ago

Which of the following is the best strategy to support children in learning about shapes?

Sunny_sXe [5.5K]

The best option is C. Provide multiple worksheets with pictures of the basic shapes for children to colour.

<h3>What does the learning process in children involve?</h3>

The process of learning has often been described to include all but not limited to the following:

gaining new understanding,

learning new behaviours,
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babymother [125]

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Written as a/b, read as "a by b", it functions as a number of parts of a total of b number of parts.

In the question, we are given that Tayloe travels 35 miles every 2 days to work.

Therefore, daily traveling done by Tayloe can be shown as a fraction, 35/2 miles.

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Thus, the number of days Tayloe will take to travel 100 miles can be shown in fractional form as 100/(35/2) = (100*2)/35 = 40/7 or 5 5/7.

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