Answer:
A) B is greater
B) when C = 21, A = 5 and B = 15
C) A must be 0, 5, or 12 for C to be greater than B
Step-by-step explanation:
A) when a = -3, c = -20 and b = 4(-3)-5 so B = -17
B) when c = 21, a = 5 and b = 4(5)-5 so B = 15
C) C is greater than B when a = 0, 5, and 12
when a = 0, b = 4(0)-5 or -5
when a = 5, b = 4(5)-5 or 15
when a = 12, b = 4(12)-5 or 43
Answer:
The frequency of the given sinusoidal graph is 4.
Step-by-step explanation:
The frequency of a sinusoidal graph is the number of cycles it completes in the interval 0 to 2π radians.
From the given sinusoidal graph it is noticed that the the graph complete its one cycle in the interval 0 to
.
If the complete its one cycle in
, then the number of cycles completed by the graph in the inteval 0 to 2π is



Therefore the frequency of the given sinusoidal graph is 4.
V=hpir^2
SA=2pir^2+2hpir
a.
SA=2pi9^2+2*36pi9
SA=2pi81+72pi9
SA=162pi+648pi
SA=810pi in^2
b.
aprox pi=3.14
810*3.14=2542.4cm^2
c.
V=36pi9^2
V=36pi81
V=2916pi in^3
d. 3.14=pi
2916*3.14=9156.24 in^3
<h3>Answer 1a :- </h3>
Here we can solve this question using<em> </em><em>Unitary</em><em> </em><em>Method</em><em> </em><em>.</em> As ;
→ In 17hrs the boat travels 452km
→ In 1hr the boat will travel 452km/17
→ In 9hrs the boat will travel 452/17km * 9 = 239.29km

<h3>Answer 1b:-</h3>
→ A car can travel 156km on 13L gasoline .
→ It will travel 1km on 13/156L of gasoline .
→ It will travel 480km on 13/156*480L = 40L of gasoline .

<h3>
Answer 2a :-</h3>
→ A boat can go 180 miles on 60L gasoline.
→ It will go 1mile in 60/180L of gasoline.
→ It will go 306 miles in 60/180*306L = 102L of gasoline .

<h3>Answer 2b :-</h3>
→ On 51L of gasoline a car can go 408km
→ On 1L of gasoline car will go 408/51 km
→ On 11L of gasoline it will go 408/51*11L = 88km
