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andreev551 [17]
2 years ago
14

How many solutions does the following system of equations have?

Mathematics
1 answer:
Karo-lina-s [1.5K]2 years ago
5 0

Answer:

these equation hv 1 solution

like this

Step-by-step explanation:

may be this one help u then plz mark me briallent

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What is an equation of the line that passes through the points (-6, -2) and
den301095 [7]

Answer:

The equation of line is: \mathbf{4x-3y=-18}

Step-by-step explanation:

We need to find an equation of the line that passes through the points (-6, -2) and  (-3, 2)?

The equation of line in slope-intercept form is: y=mx+b

where m is slope and b is y-intercept.

We need to find slope and y-intercept.

Finding Slope

Slope can be found using formula: Slope=\frac{y_2-y_1}{x_2-x_1}

We have x_1=-6,y_1=-2, x_2=-3, y_2=2

Putting values and finding slope

Slope=\frac{2-(-2)}{-3-(-6)}\\Slope=\frac{2+2}{-3+6} \\Slope=\frac{4}{3}

So, we get slope: m=\frac{4}{3}

Finding y-intercept

Using point (-6,-2) and slope m=\frac{4}{3} we can find y-intercept

y=mx+b\\-2=\frac{4}{3}(-6)+b\\-2=4(-2)+b\\-2=-8+b\\b=-2+8\\b=6

So, we get y-intercept b= 6

Equation of required line

The equation of required line having slope m=\frac{4}{3} and y-intercept b = 6 is

y=mx+b\\y=\frac{4}{3}x+6

Now transforming in fully reduced form:

y=\frac{4x+6*3}{3} \\y=\frac{4x+18}{3} \\3y=4x+18\\4x-3y=-18

So, the equation of line is: \mathbf{4x-3y=-18}

6 0
2 years ago
(100 points)
LekaFEV [45]

Answer:

30/10 and 5/11

Step-by-step explanation:

8 0
3 years ago
Which type of function best models the given data?
kherson [118]

Answer:

3)

Step-by-step explanation:

Draw the graph and youll see

5 0
2 years ago
Read 2 more answers
What is the circumference of the circle defined by x^2+6x +y^2-12y-4=0.
KengaRu [80]

Answer:

44.0

Step-by-step explanation:

Mark me as brainliest

5 0
3 years ago
Two equivalent equations of the line in point slope form for (-4,8) and (0,5)
34kurt

Answer:

Equation of line 1  is 3 X - 4 Y = 20

Equation of line 2 is 3 X  + 4 Y = 20

Step-by-step explanation:

Given co ordinates of points as,

( -4 , 8)  and (0 , 5)

From the given two points we can determine the slop of a line

I. e slop (m) = \frac{(y2 - y1)}{(x2 - x1)}

Or,           m  = \frac{(5 - 8)}{(0 + 4)}

So,           m = \frac{(-3)}{(4)}

Now equations of line can be written as ,

Y - y1 = m ( X - x1)

<u>At points ( -4 , 8)</u>

Y - 8   = \frac{(-3)}{(4)} (X + 4)

So , Equation of line 1  is 3 X - 4 Y = 20

<u>Again with points ( 0 , 5)</u>

Y - 5   = \frac{(-3)}{(4)} ( X - 0)

So, Equation of line 2 is 3 X  + 4 Y = 20

Hence Equation of line 1  is 3 X - 4 Y = 20  and Equation of line 2 is 3 X  + 4 Y = 20   Answer

4 0
3 years ago
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