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Arturiano [62]
3 years ago
8

What number goes into both 14 and 49?

Mathematics
1 answer:
kirill [66]3 years ago
5 0
7 goes into both 14 and 49. 7 divided by 14 is two and 7 divided by 49 is seven.
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Only 18 people are allowed on a ride at the same time. There are 157 people waiting in line. How many groups of riders will ther
IrinaK [193]

Answer:

Step-by-step explanation:

Divide 157 by 8 to see how many groups there are.

157/18=8r13. So you can round up to 9 groups of riders as there is a max of 18 at a time.

7 0
3 years ago
1. Find the value of
spin [16.1K]

9514 1404 393

Answer:

  1. -√5
  2. 3/5
  3. -4/5

Step-by-step explanation:

The relevant relations are ...

  sec = ±√(tan² +1)

  cos = 1/sec

  csc = 1/sin = ±1/√(1 -cos²)

Sine and Cosecant are positive in quadrants I and II. Cosine and Secant are positive in quadrants I and IV.

__

1. sec(θ) = -√((-2)² +1) = -√5

2. cos(θ) = 1/sec(θ) = 1/(5/3) = 3/5

3. csc(θ) = -1/√(1 -(-3/5)²) = -√(16/25) = -4/5

8 0
2 years ago
If, while training for a marathon, you ran 76 miles in 2 2/3 months, how many miles did you run each month? (Assume you ran the
Gnesinka [82]
In 2 2/3 months you ran 76 miles.
To know how many miles you ran each month, you can simply use cross multiplication as follows:
number of miles per month= (76) / (2 2/3)
= 28.5 miles
3 0
3 years ago
A small telescope magnifies
WARRIOR [948]

The observatory telescope has 22 times the magnifying power compared to the small telescope.

Data;

  • small telescope = 150 times
  • large telescope = 3300

<h3>Division of Numbers</h3>

To solve this question, we have to divide the large telescope by the small telescope to calculate it's magnifying power.

x = \frac{3300}{150}=22

The magnification of the observatory telescope is 22 times greater or larger than the small telescope.

Learn more on division of numbers here;

brainly.com/question/7068223

4 0
2 years ago
Examine the diagram at right. The smaller triangle (inside of the larger triangle) is similar to larger triangle. How can you so
olchik [2.2K]

As the exercise says, the triangles are similar. So, we can set up proportions between correspondent sides.

In order to solve for x we can set up the proportion between the horizontal and vertical sides:

28\div 11.2 = 27+x \div x

Solving this proportion for x implies x=18

Now you can solve for m and p using the pythagorean theorem, because both triangles are right:

m = \sqrt{18^2+11.2^2} =21.2

Then, we know that the hypothenuse of the big triangle is m+p, so we have

m+p=\sqrt{(18+27)^2+28^2} = 53

which implies

p = 53-p = 53-21.2=31.8

6 0
2 years ago
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